检查表中用户存在问题

Question

如果$name和$email与现有记录不匹配，但下面的代码段插入与另一个客户端相同的记录，我尝试在以下位置阻止： if($stmt->num_rows > 0) {}

<?php 

include_once"dbconfig.php"; 
$name = "aaa"; 
$email = "a@a.a"; 
$phone = "666"; 
$mysqli = new mysqli(DB_HOST, DB_USER, DB_PASS, DB_DATABASE); 
if ($mysqli->connect_error) { 
    die('Error : ('. $mysqli->connect_errno .') '. $mysqli->connect_error); 
} 
$sql = "SELECT id, name, email,phone FROM `clients` WHERE `email` = '". $email."' AND `phone` = ". $phone; 
$stmt = $mysqli->prepare($sql); 
$stmt->execute(); 
$stmt->bind_result($id, $name, $email, $phone); 
$stmt->store_result(); 

if($stmt->num_rows > 0) { 
     echo "This Email already is in system"; 
    }else{ 
     $stmt = $mysqli->prepare("INSERT INTO clients (`name`,`email`,`phone`) VALUES (?, ?, ?)"); 
     $stmt->bind_param("sss", $email, $phone, $name); 
     $stmt->execute(); 
     echo "New records created successfully"; 
    } 
$stmt->close(); 
$mysqli->close(); 

?> 

你能让我知道我在做什么错吗？

Answer 1

试试这个，

$sql = "SELECT id, name, email FROM `clients` WHERE `email` = '". $email."' AND `phone` = ". $phone; 

Answer 2

我认为问题出在你的SQL语句，你检查记录，则在：

'电话'>” $电话