关闭Android应用程序破坏广播接收机

Question

在主要活动在onCreate方法我注册broadcastReciver但在关闭应用程序，我总是得到这个错误：当我关闭应用程序，我不想注销接收器

@429d47e0 that was originally registered here. Are you missing a call to unregisterReceiver()? 
04-10 23:40:48.161: E/ActivityThread(20989): at android.app.LoadedApk$ReceiverDispatcher.<init>(LoadedApk.java:793) 
04-10 23:40:48.161: E/ActivityThread(20989): at android.app.LoadedApk.getReceiverDispatcher(LoadedApk.java:593) 
04-10 23:40:48.161: E/ActivityThread(20989): at android.app.ContextImpl.registerReceiverInternal(ContextImpl.java:1274) 
04-10 23:40:48.161: E/ActivityThread(20989): at android.app.ContextImpl.registerReceiver(ContextImpl.java:1261) 
04-10 23:40:48.161: E/ActivityThread(20989): at android.app.ContextImpl.registerReceiver(ContextImpl.java:1255) 
04-10 23:40:48.161: E/ActivityThread(20989): at android.content.ContextWrapper.registerReceiver(ContextWrapper.java:372) 

。我能做什么？我以编程方式注册接收者。

Answer 1

when I close application I don't want to unregister receiver

然后，您不应该通过registerReceiver()注册它。改为通过<receiver>元素将其注册到清单中。然后，无论您的应用程序是否正在运行，它都可用。