2017-04-26 309 views
0

我遇到了一个问题,我无法在服务器端获取我的对象。 我收到此错误:无法读取HTTP消息。所需的请求正文缺失

128870 [http-apr-8080-exec-1] WARN org.springframework.web.servlet.mvc.support.DefaultHandlerExceptionResolver - Failed to read HTTP message: org.springframework.http.converter.HttpMessageNotReadableException: Required request body is missing: public com.webserverconfig.user.entity.User com.webserverconfig.user.controller.UserController.login(com.webserverconfig.user.entity.User) 

我试图用GET请求在服务器端发送的对象。我想用这个对象来验证它上面的字段。 (我正在做简单的用户登录方法,我想检查userNameuserPassword)。

这是我在服务器端代码: 请求:

@RequestMapping(value = "/login", method = RequestMethod.GET) 
    @ResponseStatus(value = HttpStatus.ACCEPTED) 
    public User login(@RequestBody User user) { 
     userValidator.validateUserLogin(user); 
     securityService.autoLogin(user.getUserName(), user.getUserPassword()); 
     return user; 
    } 

实体用户:

@Entity 
@Table(name = "Users") 
public class User { 
    public User() { 
    } 

    @Id 
    @GeneratedValue(generator = "increment") 
    @GenericGenerator(name = "increment", strategy = "increment") 
    @Column(name = "Id", unique = true, nullable = false) 
    private long id; 

    @Column(name = "userName", nullable = false) 
    private String userName; 

    @Column(name = "userPassword", nullable = false) 
    private String userPassword; 

    @Transient 
    private String confirmPassword; 


    public long getId() { 
     return id; 
    } 

    public String getUserName() { 
     return userName; 
    } 

    public String getUserPassword() { 
     return userPassword; 
    } 

    public String getConfirmPassword() { 
     return confirmPassword; 
    } 

    public void setId(long id) { 
     this.id = id; 
    } 

    public void setUserName(String userName) { 
     this.userName = userName; 
    } 

    public void setUserPassword(String userPassword) { 
     this.userPassword = userPassword; 
    } 

    public void setConfirmPassword(String confirmPassword) { 
     this.confirmPassword = confirmPassword; 
    } 
} 

客户端代码:

private class LoginUserTask extends AsyncTask<Void, Void, User> { 
     @Override 
     protected User doInBackground(Void... voids) { 
      restTemplate = new RestTemplate(); 
      restTemplate.getMessageConverters().add(new MappingJackson2HttpMessageConverter()); 
      User user = new User(userName, userPassword); 
      return restTemplate.getForObject(URL.getUserLogin(), User.class, user); 
     } 

     @Override 
     protected void onPostExecute(User user) { 
      responseEntity = restTemplate.getForEntity(URL.getUserLogin(), String.class); 
      HttpStatus responseStatus = responseEntity.getStatusCode(); 
      if(responseStatus.equals(HttpStatus.ACCEPTED)){ 
       view.makeToast("User login completed " + user.getUserName()); 
      } else { 
       view.makeToast("User login or password is not correct"); 
      } 
     } 
    } 

我缺少的东西?任何人都可以帮忙吗?

+0

'onPostExecute',但您正在检查'get'请求?所以你的'login'函数中没有找到正文,你可能有'@ RequestBody'注解? – Nathan

+0

@Nathan我是否使用错误的请求方法?我的意思是 - GET – Andrew

+0

@Nathan哦,我想我明白了。我应该在getForEntity方法中发送对象吗? – Andrew

回答

3

您已经将User对象设置为@RequestBody注释作为输入参数。 在这种情况下,您必须在请求正文中使用POST方法和User对象。

+0

这是工作谢谢你。 – Andrew

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