用于比较2个CSV的丢失元素的函数

Question

我正在编写一个函数来比较两个CSV，但一旦我找到比较部分，就会收到错误。 我只想指出那些列入其中之一的元素。

实际代码

function Compare ($location1, $location2) 
{ 
    #work in progress 
    $CSV1 = Import-Csv -Path $location1 -UseCulture 
    $CSV2 = Import-Csv -Path $location2 -UseCulture 
    $Compared = Compare-Object -ReferenceObject $CSV1 -DifferenceObject $CSV2 | 
       select -ExpandProperty InputObject | 
       sort 
    [void] $CSV1 
    [void] $CSV2 
    return $Compared 
} 

和来自两个CSV的一个片段：

列表A：

 
a 
b 
c 
d 
e 
f 
g 

片段B：

 
a 
b 
c 
d 
e 
h 
f 
g 
h 
i 
j 

那些是用于测试目的看看它是否rks，但现在它甚至没有开始比较。

当我在控制台中查找时，两个CSV会正确加载。

Answer 1

我会去这样的：

我已经添加了名为“名称”的第一行上的列名。因此，使用该设置，您可以将其作为属性进行访问。 所以

$CSV1 = $null 
$CSV2 = $null 

$CSV1 = Import-Csv -Path 'C:\temp\pos\reference.csv' 
$CSV2 = Import-Csv -Path 'C:\temp\pos\difference.csv' 

$dif = Compare-Object -ReferenceObject $CSV1 -DifferenceObject $CSV2 -Property Name 

foreach($y in $dif){ 
    if($y.SideIndicator -eq "=>"){ 
    write-output $y.name "Is present in the difference but not in reference." 
    } 
    if($y.SideIndicator -eq "<="){ 
    write-output $y.Name "Is present in reference but not in difference" 
    } 

} 

<# content csv1 (reference.csv) 
Name 
a 
b 
c 
5 
d 
e 
f 
g 
9 
#> 
<#content csv2 (difference.csv) 
Name 
a 
b 
c 
d 
e 
f 
g 
h 
i 
j 
k 
l 
m 
n 
o 
p 
#> 

这会给我的输出：

h Is present in the difference but not in reference. 
i Is present in the difference but not in reference. 
j Is present in the difference but not in reference. 
k Is present in the difference but not in reference. 
l Is present in the difference but not in reference. 
m Is present in the difference but not in reference. 
n Is present in the difference but not in reference. 
o Is present in the difference but not in reference. 
p Is present in the difference but not in reference. 
5 Is present in reference but not in difference 
9 Is present in reference but not in difference 

Answer 2

恐怕比较对象不喜欢的工作。根据我的理解，你正试图在两者中找到独特的物品。最简单的方法是将两个CSV添加在一起，然后在要获取唯一属性的属性上执行select-object -Unique。

($csv1 + $csv2).Name | Select-Object -Unique 

在这里，我认为在CSV数据的列名是“名称”