5
我想(静态)反映样本类是这样的:在scala 2.11中反映case class字段的最佳方法是什么?
case class Foo[T,U](stuff:T, more:U, age:Int) {
val ignore:Boolean = false
}
我开始是这样的:
val symbol = currentMirror.classSymbol(clazz) // symbol is universe.ClassSymbol
// I want to know about type placeholders T and U
val typeParamArgs = symbol.typeParams.map(tp => tp.name.toString)
if(symbol.isCaseClass) {
val tsig = symbol.typeSignature
println(tsig)
}
好吧,在这一点上,如果我打印TSIG我看到:
[T, U]scala.AnyRef
with scala.Product
with scala.Serializable {
val stuff: T
private[this] val stuff: T
val more: U
private[this] val more: U
val age: scala.Int
private[this] val age: scala.Int
def <init>(stuff: T,more: U,age: scala.Int): co.blocke.Foo[T,U]
val ignore: scala.Boolean
private[this] val ignore: scala.Boolean
def copy[T, U](stuff: T,more: U,age: scala.Int): co.blocke.Foo[T,U]
def copy$default$1[T, U]: T @scala.annotation.unchecked.uncheckedVariance
def copy$default$2[T, U]: U @scala.annotation.unchecked.uncheckedVariance
def copy$default$3[T, U]: scala.Int @scala.annotation.unchecked.uncheckedVariance
override def productPrefix: java.lang.String
def productArity: scala.Int
def productElement(x$1: scala.Int): scala.Any
override def productIterator: Iterator[scala.Any]
def canEqual(x$1: scala.Any): scala.Boolean
override def hashCode(): scala.Int
override def toString(): java.lang.String
override def equals(x$1: scala.Any): scala.Boolean
}
看到中间那条线<init>?这是我想要反思的声明。它有我需要的。
我该如何区分tsig(universe.Type)以获得有关< init的信息>?(我不想对“忽略”的信息。)