如何使用sequelize + mysql + express js处理文件上传？

Question

我正在开发一个需要pdf/doc文件上传的简单软件大学项目。但是这里出现了瓶颈：我无法在任何地方找到使用Sequelize ORM的此功能的示例和示例。

有没有人用这个框架做过类似的事情？

*顺便说一句，我知道有几个npm包express（），但我必须使用sequelize。

欢迎任何建议。

在此先感谢;）

Answer 1

配置与multer快递应用。阅读过的multer的文件，但总之你存储上传的文件的路径：

const multer = require('multer') 
const express = require('express') 
const Sequelize = require('sequelize') 
const sequelize = new Sequelize('database', 'username', 'password') 

const MyModel = sequelize.define('myModel', { 
    filePath: Sequelize.STRING, 
}) 

const express = express() 

const storage = multer.diskStorage({ 
    destination: (req, file, cb) => { 
    cb(null, './app/uploads') 
    }, 
    filename: (req, file, cb) => { 
    cb(null, file.originalname) 
    } 
}) 

app.post('/upload', multer({ storage }).single('example), async (req, res) => { 
    // This needs to be done elsewhere. For this example we do it here. 
    await sequelize.sync() 

    const filePath = `${req.file.destination}/${req.file.filename}` 

    const myModel = await MyModel.create({ filePath }) 
}) 

Answer 2

一个使用AJAX稍微简单的例子（from）。

添加到您的Node.js

var multer = require('multer'); 

const storage = multer.diskStorage({ 
    destination: (req, file, callback) => { 
     console.log(req); 
     callback(null, './uploads'); 
    }, 
    filename: (req, file, callback) => { 
     console.log(req); 
     callback(null, Date.now() + file.originalname); 
    } 
}); 

var upload = multer({storage:storage}).single('myFile'); 

app.post('/dashboard/myFile', function(req,res){ 
     upload(req,res,function(err){ 
      //console.log("owen",req.file,err); 
      if (err) 
       return res.end("error uploading file"); 
      res.end("file is uploaded"); 
     }); 
}); 

而在你的HTML

<form id="myForm" name="myForm" enctype="multipart/form-data" method="post"> 
    <input id="myFile" name="myFile" type="file"> 
    <button type="submit" class="btn btn-primary">Submit</button> 
</form> 


<script> 

var form = document.forms.namedItem("myForm"); 

form.addEventListener('submit', function(ev){ 
    var myFile = document.getElementById('myFile').files[0]; 
    var oData = new FormData(form); 
    var oReq = new XMLHttpRequest(); 
    oReq.open("POST","/uploadFile",true); 
    oReq.onload = function(oEvent){ 
     if(oReq.status == 200) { 
      console.log("success",oEvent); 
     } else { 
      console.log("fail",oEvent); 
     } 
    } 
    oReq.send(oData); 
    ev.preventDefault(); 
},false); 

</script>