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下面是用户列表webservice的json响应的代码。Codeigniter中的Json响应
<?php if (! defined('BASEPATH')) exit('No direct script access allowed');
class Webservice extends CI_Controller
{
function list_user()
{
$result_login = $this->db->get('user_registration')->result();
$response = array();
$response ["success"] = 1;
$response ["message"] = "User List.";
foreach($result_login as $row)
{
$data = array();
$data['User Id'] = $row->user_id;
$data['Name'] = $row->name;
$data['Email'] = $row->email;
$data['mobile_number'] = $row->mobile_number;
$data['Password'] = $row->password;
$output2 = json_encode(array('responsedata' => $data));
echo $output2;
}
}
}
?>
在我的代码中,如果我用json_encode中的$ response替换$ data,那么我无法获得$ data的值。 我以这种格式得到了json响应。 JSON响应。
{
"responsedata": {
"User Id": "7",
"Name": "bhavin",
"Email": "[email protected]",
"mobile_number": "123456789",
"Password": "abc"
}
}
但我想要这种格式的json响应。
{
"responsedata":
{
"success": 1,
"data": [
{
"User Id": "7",
"Name": "test",
"Email": "[email protected]",
"mobile_number": "123456789",
"Password": "abc"
},
{
"User Id": "8",
"Name": "test2",
"Email": "[email protected]",
"mobile_number": "123456789",
"Password": "abc"
}
]
}
}
我试着用上面的代码,但我不能得到结果。我在$ data ['data'] = $ array_of_event中遇到问题。我如何获取一个一个行,并在最后我使用json_encode进行编码。 – Bhavin