读取一个特定的信息并使用java写入一个txt文件

Question

对于java编程来说是新的我需要一个程序来读取文件中的特定信息并选择所需的特定信息，然后将这些特定信息写入文本文件。

{

BufferedReader in = new BufferedReader (newFileReader("C:/Users/ngorentl/")); 
    String info = ""; 
    String info1 = ""; 
    int startLine = 111 ; 
    int endLine = 203 ; 
    int sl = 221; 
    int el =325; 

//只读取其中需要和在控制台打印

for (int i = 0; i < startLine; i++) { info = in.readLine(); } 
    for (int i = startLine; i < endLine + 1; i++) { 
     info = in.readLine(); 
     System.out.println(info); 
    } 
     for (int j = 203; j < sl; j++) { info1 = in.readLine(); } 
     for (int j = sl; j < el + 1; j++) { 
      info1 = in.readLine(); 
      System.out.println(info1); 
     } 

    // having a problem from here i dont know whether this is the correct approach 
     File fin = new File(info); // getting an error here 
     FileInputStream fis = new FileInputStream(fin); 
     BufferedReader is = new BufferedReader(new InputStreamReader(fis));  
     FileOutputStream fos = new FileOutputStream("hh.txt"); 
     OutputStreamWriter osw= new OutputStreamWriter(fos); 
     BufferedWriter bw = new BufferedWriter(osw); 
     String aLine = null; 
     while ((aLine = is.readLine()) != null) { 
     bw.write(aLine); 
     bw.newLine(); 
     bw.flush(); 
     bw.close(); 
     is.close(); 
     } 
     in.close(); 

特定信息}

Answer 1

文件鳍=新的文件（字符串文件名）是正确的语法。 例如。 File fin = new File（“C：\ abc.txt”）;

[更新] 假设你的问题是关于写一个String到文件。 在Java 7

try( PrintWriter out = new PrintWriter("filename.txt") ){ 
out.println(info); 
} 

在Java 6或以下，用你的代码的

try { 
     BufferedWriter out = new BufferedWriter(new FileWriter("sample.txt")); 
     out.write(info); 
     out.close(); 
    } 
    catch (IOException e) 
    { 
     System.out.println("Exception ");  
    } 

和可能的修正，所以可变信息具有所有信息

for (int i = startLine; i < endLine + 1; i++) { 
    info += in.readLine(); 
} 

    System.out.println(info);