PHP的preg_match圣经经文格式

Question

我与建立一个正则表达式解析这种字符串（圣经经文）挣扎：

'John 14:16–17, 25–26' 
    'John 14:16–17' 
    'John 14:16' 
    'John 14' 
    'John' 

所以基本模式是：

Book [[Chapter][:Verse]]

哪里章节和诗节是可选的。

Answer 1

试试这个位置

\b[a-zA-Z]+(?:\s+\d+)?(?::\d+(?:–\d+)?(?:,\s*\d+(?:–\d+)?)*)? 

看到和测试here on Regexr

因为(?:,\s*\d+(?:–\d+)?)*在年底可以有经文列表，经文范围结尾。

Answer 2

使用这个表达式：

[A-Za-z]+(([0-9]+)(:[0-9]+)?([\-–][0-9]+)?(, [0-9]+[\-–][0-9]+)?)? 

或者在它的 '漂亮' 的版本：

\w+((\d+)(:\d+)?([\-–]\d+)?(, \d+[\-–]\d+)?)? 

---

更新：要匹配破折号或连字符

---

NOTE：我测试过它，它匹配所有5个可能的版本。

例子：http://regexr.com?30h4q

Answer 3

我认为这确实你需要：

\w+\s?(\d{1,2})?(:\d{1,2})?([-–]\d{1,2})?(,\s\d{1,2}[-–]\d{1,2})? 

假设：

• 的数字总是在套1或2位数字
• 破折号将匹配以下-和–

下面是正则表达式与评论：

" 
\w   # Match a single character that is a “word character” (letters, digits, and underscores) 
    +   # Between one and unlimited times, as many times as possible, giving back as needed (greedy) 
\s   # Match a single character that is a “whitespace character” (spaces, tabs, and line breaks) 
    ?   # Between zero and one times, as many times as possible, giving back as needed (greedy) 
(   # Match the regular expression below and capture its match into backreference number 1 
    \d   # Match a single digit 0..9 
     {1,2}  # Between one and 2 times, as many times as possible, giving back as needed (greedy) 
)?   # Between zero and one times, as many times as possible, giving back as needed (greedy) 
(   # Match the regular expression below and capture its match into backreference number 2 
    :   # Match the character “:” literally 
    \d   # Match a single digit 0..9 
     {1,2}  # Between one and 2 times, as many times as possible, giving back as needed (greedy) 
)?   # Between zero and one times, as many times as possible, giving back as needed (greedy) 
(   # Match the regular expression below and capture its match into backreference number 3 
    [-–]  # Match a single character present in the list “-–” 
    \d   # Match a single digit 0..9 
     {1,2}  # Between one and 2 times, as many times as possible, giving back as needed (greedy) 
)?   # Between zero and one times, as many times as possible, giving back as needed (greedy) 
(   # Match the regular expression below and capture its match into backreference number 4 
    ,   # Match the character “,” literally 
    \s   # Match a single character that is a “whitespace character” (spaces, tabs, and line breaks) 
    \d   # Match a single digit 0..9 
     {1,2}  # Between one and 2 times, as many times as possible, giving back as needed (greedy) 
    [-–]  # Match a single character present in the list “-–” 
    \d   # Match a single digit 0..9 
     {1,2}  # Between one and 2 times, as many times as possible, giving back as needed (greedy) 
)?   # Between zero and one times, as many times as possible, giving back as needed (greedy) 
" 

这里是在PHP中的一些用法示例：

if (preg_match('/\w+\s?(\d{1,2})?(:\d{1,2})?([-–]\d{1,2})?(,\s\d{1,2}[-–]\d{1,2})?/', $subject)) { 
    # Successful match 
} else { 
    # Match attempt failed 
} 

获取给定字符串中所有匹配的数组

preg_match_all('/\w+\s?(\d{1,2})?(:\d{1,2})?([-–]\d{1,2})?(,\s\d{1,2}[-–]\d{1,2})?/', $subject, $result, PREG_PATTERN_ORDER); 
$result = $result[0]; 

Answer 4

([1|2|3]?([i|I]+)?(\s?)\w+(\s+?))((\d+)?(,?)(\s?)(\d+))+(:?)((\d+)?([\-–]\d+)?(,(\s?)\d+[\-–]\d+)?)? 

适用于几乎每本书...

Answer 5

(\b[a-zA-Z]\w+\s\d+)(:\d+)+([-–]\d+)?([,;](\s)?(\d+:)?\d+([-–]\d+)?)? 

这是这里介绍的所有代码的混合。唯一的格式，它不会强调是“书名只”或“书&节只”（刚加入“：1，所有”后章＃）我发现提供给有资格太多变化的其他代码，不符合圣经经文的语法。

这些是我在RegExr测试的例子：（不能发表图片尚未）

约翰 洪堡14：16-17，25-26
约14： 16-17
约翰14:16
约翰77：3; 2：9-11
约5：1-所有 布拉德555-783-6867
约翰6
您好你怎么样
斯拉32：5约14 ：16-17，25-36
23时34分
约14：16-17,25-36
约翰福音14：16-17; 32:25