2012-07-27 94 views
0

我得到了从json中解析出来的表视图string.everthing很好用.if im在我的搜索栏中输入一个字符即时获取该错误'-[__NSCFString countByEnumeratingWithState:objects:count:]: unrecognized selector sent to instance 0x1d52ac50'下面是code.were下面变量名称数据是NSMutableArray.could你们帮助我。使用搜索栏搜索tableview时出现NCFString错误

- (BOOL)searchDisplayController:(UISearchDisplayController *)controllershouldReloadTableForSearchString:(NSString *)searchString 
    { 
[searchData removeAllObjects]; 

NSArray *group; 
for(group in nameData) 
{ 
    NSLog(@"wat am i doing here:%@",group); 
    NSMutableArray *newGroup = [[NSMutableArray alloc] init]; 
    NSString *element; 

    for(element in group) 
    { 
     NSRange range = [element rangeOfString:searchString options:NSCaseInsensitiveSearch]; 

     if (range.length > 0) { 
      [newGroup addObject:element]; 
     } 
    } 

    if ([newGroup count] > 0) { 
     [searchData addObject:newGroup]; 
    } 

} 

return YES; 
} 
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所以'nameData'是可变的阵列的可变数组?这就是你如何处理它。此外,为什么在使用快速枚举时分配'group'? – trojanfoe 2012-07-27 10:53:12

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其实组是数组类型..即时通讯得到崩溃 – user578386 2012-07-27 10:54:45

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所以'nameData' **是**数组数组?是或否。 – trojanfoe 2012-07-27 10:57:40

回答

1

请看看这个代码

- (BOOL)searchDisplayController:(UISearchDisplayController *)controller shouldReloadTableForSearchString:(NSString *)searchString 
{ 
    NSMutableArray *array=[[NSMutableArray alloc]init]; 
    NSDictionary *naming= [self.friendsDictionary objectForKey:@"data"]; 
    NSLog(@"ggg %@",[self.friendsDictionary objectForKey:@"data"]); 
    for(int i =0 ; i< [[self.friendsDictionary objectForKey:@"data"] count]; i++){ 
     [array addObject:[[[self.friendsDictionary objectForKey:@"data"] objectAtIndex:i] objectForKey:@"name"]]; 
    } 
    NSLog(@"Array %@", array); 

    if(self.searchDisplayController.searchBar.text.length>0) 
    { 
     NSString *strSearchText = self.searchDisplayController.searchBar.text; 
     NSMutableArray *group = [[NSMutableArray alloc]init]; 
     for (int i=0; i<array.count; i++) { 

      NSString *strData = [array objectAtIndex:i]; 
       NSLog(@"string Data:%@",strData); 
      NSRange rng = [strData rangeOfString:strSearchText options:NSCaseInsensitiveSearch]; 
      if(rng.location != NSNotFound) 
      { 
       if(rng.location== 0)//that is we are checking only the start of the names. 
       { 
        [group addObject:strData]; 
       } 
      } 
     } 
     if ([group count] > 0) 
     { 
    searchData = [[NSMutableArray alloc] init]; 
      [searchData addObjectsFromArray:group]; 
      NSLog(@"Sear %@", searchData); 

     } 
    } 
    return YES; 
    } 
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如果刚刚分配了'group',那么for()'语句不起作用,因为'group'将是空的。 – trojanfoe 2012-07-27 11:01:09

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@trojanfoe感谢您的纠正 – Hiren 2012-07-27 11:07:08

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仍然出现错误。'[ - NSCFString计数]:无法识别的选择器发送到实例0x1bc3d0' – user578386 2012-07-27 11:22:48