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我正在尝试上传图片与服务器。 在Android中,它的工作完美与此代码:用Alamofire和MultiFormData上传图片
RestTemplate restTemplate = new RestTemplate();
MultiValueMap<String, Object> map = new LinkedMultiValueMap<String, Object>();
String strPath = "D:\\Personal\\Projects\\Resources\\Images\\ic_flash_on.png";
Path path = Paths.get(strPath);
byte[] bytes = Files.readAllBytes(path);
map.add("id", 2);
map.add("file", new ByteArrayResource(bytes) {
@Override
public String getFilename() {
return "ic_flash_on.png";
}
});
HttpHeaders headers = new HttpHeaders();
headers.setContentType(MediaType.MULTIPART_FORM_DATA);
headers.add("Authorization", request.getHeader("Authorization"));
HttpEntity<MultiValueMap<String, Object>> imageEntity = new HttpEntity<MultiValueMap<String, Object>>(map, headers);
ResponseEntity<Photo> result = restTemplate.exchange("http://localhost:8080/api/photos/upload", HttpMethod.POST,
imageEntity, Photo.class);
return result;
在iOS中,我使用Alamofire与代码:
let url = HOST + "api/photos/upload"
let accessToken = KeychainHelper.getStringForKey(KeychainConstaint.kAccessTokenKey) ?? ""
let headers = [
"Authorization": "Bearer \(accessToken)",
"Content-Type": "multipart/form-data"
]
Alamofire.upload(
.POST,
url,
headers: headers,
multipartFormData: { multipartFormData in
var id = 10000
let idData = NSData(bytes: &id, length: sizeof(Int))
//multipartFormData.appendBodyPart(data: photo.data, name: "file")
multipartFormData.appendBodyPart(data: idData, name: "id")
multipartFormData.appendBodyPart(data: photo.data, name: "file", fileName: ".jpg", mimeType: "image/jpeg")
},
encodingMemoryThreshold: Manager.MultipartFormDataEncodingMemoryThreshold) { encodingResult in
switch encodingResult {
case .Success(let upload, _, _):
upload.responseJSON { response in
debugPrint(response)
}
case .Failure(let encodingError):
print(encodingError)
}
}
而且它会失败,原因是:“必需MultipartFile参数 '文件' 是不是礼物“
我错过了什么吗? :(
我听到你们的斗争,我有现在的样子看起来像一个类似的问题。对我来说,它与参数“withName”和“文件名”中multipartFormData.append()调用来完成。 我会建议,如果你有控制Spring后端,添加一个带有断点的“Filter”类,你可以调查'好'和'坏'请求,看看到底有什么不同(它会到达断点 – MikaelW
嗨,我发现文件名:不应该格式化为这样的“.jpg” 我在该函数中冲突了'name'参数和'fileName'。 –