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我想设计一个程序,输出给定一定数量的术语运行的每个斐波那契数的模数。我也希望这个程序输出的数字是偶数,可以被5整除,或者是全零。所以基本上它需要每循环运行三分之一,五分之一和十五分之一时的特定输出,因此我试图使用一堆if语句。如果你可以请指导我在正确的方向或告诉我什么样的代码/格式使用,我想我会弄清楚。谢谢。如何获得for循环的特定运行时间的特定输出?
sample output: for a 17 term input
1: 1
2: 1
3: 2 - even
4: 3
5: 5 - divisible by 5
6: 8 - even
7: 3
8: 1
9: 4 - even
10: 5 - divisible by 5
11: 9
12: 4 - even
13: 3
14: 7
15: 0 - even -divisible by 5 - ends in zero
16: 7
17: 7
#include <iostream>
using namespace std;
int main()
{
int terms, n, next1, next2, first = 0, second = 1;
cout << "Welcome to the Fibonacci sequence checker!" << endl;
cout << "How many terms do you want to check?" << endl;
cin >> terms;
for (int n = 1; n < terms; n++)
{
if (n <= 1)
next2 = n;
else
{
next1 = first + second;
next2 = (first + second) % 10;
first = second;
second = next1;
}
if(next2 == 2 || next2 == 4 || next2 == 6 || next2 == 8)
{
cout << next2 << " - even";
}
if(next2 == 5)
{
cout << next2 << " - divisible by 5";
}
if(next2 == 0)
{
cout << " - even - divisible by 5 - ends in a zero";
}
}
return 0;
}
输出样本: 1:1 2:1 3:2 - 甚至 4:3 5:5 - 整除5 6:8 - 甚至 7:3 8:1 9:4 - 甚至 10:5 - 整除5 11:9 12:4 - 甚至 13:3 14:7 15:0 - 即使由5 -divisible - 终止于零 16:7 17:7
我对描述进行了修改并添加了一个示例输出。 – PrivatePatron