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摘编架构看起来像分选的结果计数从桥接表连接
表:公寓
id | city | price ...
表美化:
id | name
桥接表
Apartment_id | Amenity_id
的查询我正在尝试c onstruct会像
SELECT * FROM Apartment a
WHERE
a.`city` = 'foo'
AND a.`price` <= 'bar'
UNION
SELECT COUNT(*) as ct FROM Bridging b
WHERE a.id = b.Aprtment_id AND
(b.Amenity_id = 'x' OR b.Amenity_id = 'y' OR b.Amenity_id = 'z')
ORDER BY ct DESC
如果我的代码,我可以遍历发现公寓,查询市容比赛和分页之前添加计数字段中的对象和排序上,但是这似乎这样做非常优雅。
是一种干净的方式来查询桥接表中匹配行数排序的Aprtment记录吗?
你是男人!谢谢!请注意,应该读取COUNT(*)为ct,Apartment_id – jerrygarciuh 2011-12-30 14:16:20
谢谢,修复了我的狡猾复制/粘贴 – gbn 2011-12-30 14:17:05
如果您来到新奥尔良,我欠您的是首选饮料! – jerrygarciuh 2011-12-30 14:22:37