我有以下的模型,我想序列化通过REST暴露:Django的REST框架序列化ForeignKey的和ManyToManyFields
class RehabilitationSession(models.Model):
patient = models.ForeignKey('userprofiles.PatientProfile', null=True, blank=True,verbose_name='Paciente', related_name='patientprofile')
slug = models.SlugField(max_length=100, blank=True)
medical = models.ForeignKey('userprofiles.MedicalProfile', null=True, blank=True,
verbose_name='Médico tratante')
therapist = models.ForeignKey('userprofiles.TherapistProfile', null=True, blank=True, verbose_name='Terapeuta')
date_session_begin = models.DateTimeField(default=timezone.now(), verbose_name = 'Fecha de inicio')
upper_extremity = MultiSelectField(
max_length=255,
choices=EXTREMITY_CHOICES,
blank=False,
verbose_name='Extremidad Superior'
)
affected_segment = models.ManyToManyField(AffectedSegment,verbose_name='Segmento afectado')
movement = ChainedManyToManyField(
Movement, #Modelo encadenado
chained_field = 'affected_segment',
chained_model_field = 'corporal_segment_associated',
verbose_name='Movimiento'
)
metrics = models.ManyToManyField(Metric, blank=True, verbose_name='Métrica')
date_session_end = models.DateTimeField(default=timezone.now(), verbose_name = 'Fecha de finalización')
period = models.CharField(max_length=25,blank=True, verbose_name='Tiempo de duración de la sesión')
class Meta:
verbose_name = 'Sesiones de Rehabilitación'
def __str__(self):
return "%s" % self.patient
要序列这是外键的字段我读this documentation
我的串行的.py是这样的:
from .models import RehabilitationSession
from rest_framework import serializers
class RehabilitationSessionSerializer(serializers.HyperlinkedModelSerializer):
patient = serializers.HyperlinkedIdentityField(view_name='patientprofile',)
class Meta:
model = RehabilitationSession
fields = ('url','id','patient',
'date_session_begin','status','upper_extremity',
'date_session_end', 'period','games','game_levels',
'iterations','observations',)
我使用HyperlinkedIdentityField,由于我的模型是序列化与HyperlinkedModelSerializer
b UT,我没有明确的或者我还是不理我应该如何序列化时,一个字段是ForeignKey
和ManyToManyField
我urls.py
主文件,其中包括我的路线对设置的API网址的是:
from django.conf.urls import url, include #patterns
from django.contrib import admin
from .views import home, home_files
# REST Framework packages
from rest_framework import routers
from userprofiles.views import UserViewSet, GroupViewSet, PatientProfileViewSet
from medical_encounter_information.views import RehabilitationSessionViewSet
router = routers.DefaultRouter()
router.register(r'users', UserViewSet)
router.register(r'groups', GroupViewSet)
router.register(r'rehabilitation-session', RehabilitationSessionViewSet)
router.register(r'patientprofile', PatientProfileViewSet)
urlpatterns = [
url(r'^admin/', admin.site.urls),
url(r'^chaining/', include('smart_selects.urls')),
url(r'^$', home, name='home'),
url(r'^', include('userprofiles.urls')),
#Call the userprofiles/urls.py
url(r'^', include('medical_encounter_information.urls')),
#Call the medical_encounter_information/urls.py
# which is a regular expression that takes the desired urls and passes as an argument
# the filename, i.e. robots.txt or humans.txt.
url(r'^(?P<filename>(robots.txt)|(humans.txt))$',
home_files, name='home-files'),
#REST Frameworks url's
# Wire up our API using automatic URL routing.
# Additionally, we include login URLs for the browsable API.
url(r'^api/', include(router.urls)),
url(r'^api-auth/', include('rest_framework.urls', namespace='rest_framework')),
]
当我试图进入我的API休息的网址,我在CLI中得到以下信息:
File "/home/bgarcial/.virtualenvs/neurorehabilitation_projects_dev/lib/python3.4/site-packages/rest_framework/relations.py", line 355, in to_representation
raise ImproperlyConfigured(msg % self.view_name)
django.core.exceptions.ImproperlyConfigured: Could not resolve URL for hyperlinked relationship using view name "patientprofile". You may have failed to include the related model in your API, or incorrectly configured the `lookup_field` attribute on this field.
[08/Mar/2016 16:05:45] "GET /api/rehabilitation-session/ HTTP/1.1" 500 165647
而且在浏览器中我得到这个:
如何能序列化发生在我身上的ForeignKey和ManyToManyField相同的情况? 问候