它是我的jQuery或PHP？

Question

编辑：由于某种原因，它似乎是刷新提交按钮时的页面...任何想法？

使用ajax和kohana php框架来处理这个简单的聊天室脚本。我似乎无法让我的脚本为创建新用户工作，但我在php和javascript中有非常糟糕的调试技巧。反正我不知道是否有什么别的话来。这里是我的代码：

继承人用户类的代码：

class Model_User extends Kohana_Model 
{ 
var $_loaded = false; 
var $session = false; 
var $username = false; 
var $loginkey = false; 

function __construct() 
{ 
    $this->session = Session::instance(); 
} 

function new_user($username) 
{ 
    if($this->username_exists($username)) 
    return false; 
    $this->username = $username; 
    $this->generate_key(); 
    return $this->update_db(); 
} 

function username_exists($username) 
{ 
    if(DB::select()->from('users')->where('username', '=', $username)->execute()->count()<1); 
    return false; 
    return true; 
} 

//helper methods 

private function generate_key() 
{ 
    if(! $username) 
    return false; 
    $this->loginkey = md5($username.((int)mt_srand()*1000)); 
    $this->session->set('loginkey',$this->loginkey); 
    return true; 
} 

private function update_db() 
{ 
    if(DB::insert('users', array('username'=>$this->username, 'loginkey'=>$this->loginkey))->execute()) 
    return true; 
    return false; 
} 
    } 

和继承人的代码来处理JSON请求：

public function action_new_user(){ 
    $user = new Model_User(); 
    $json['username_exists'] = "true"; 
    $username = $_POST['username']; 
    if(isset($username)) 
    { 
    if($user->username_exists($username)) 
    { 
    echo json_encode($json); 
    return; 
    } 
    $user->new_user($_POST['username']); 
    $json['username_exists'] = "false"; 
    } 
    $this->request->response = json_encode($json); 
} 

和继承人的jQuery和HTML

<div id="chat_entry_errors"> 

</div> 

<form id="new_chat_entry" name="posttest"> 
    <input type="text" name="username" /> 
    <input type="submit" name="submit" value="New User" /> 
    </form> 

$(document).ready(function(){ 
$('#new_chat_entry').submit(function(){ 
    $.post('json/new_user', $('#new_chat_entry').serialize(), 
    function(data){ 
    if(data.username_exists=='true'){ 
    $('#chat_entry_errors').html('<div class=\"error\">Sorry that username is currently unavailable. Please choose another.</div>'); 
    } 
    else { 
    $('#chat_entry_errors').html('<div class=\"error\">Success!</div>'); 
    } 
    } 
); 
}); 
    }); 

Answer 1

看起来像它的提交表单。由于您没有操作参数，因此它会提交到同一页面，就像刷新一样。尝试将return false;添加到提交函数的末尾。

$(document).ready(function(){ 
$('#new_chat_entry').submit(function(){ 
    $.post('json/new_user', $('#new_chat_entry').serialize(), 
    function(data){ 
    if(data.username_exists=='true'){ 
    $('#chat_entry_errors').html('<div class=\"error\">Sorry that username is currently unavailable. Please choose another.</div>'); 
    } 
    else { 
    $('#chat_entry_errors').html('<div class=\"error\">Success!</div>'); 
    } 
    } 
); 
return false; 
}); 
    });