迅速的Xcode for循环阵列

Question

我确实有下一个代码，它的工作，但i'm寻找一种方法，使之更加优雅

var collectionAnswers = [0,0,1] 

if collectionAnswers[0] == 1 { 

     button1Oulet.backgroundColor = UIColor.green 
    } else { 

     button1Oulet.backgroundColor = UIColor.red 
    } 

    if collectionAnswers[1] == 1 { 

     button2Oulet.backgroundColor = UIColor.green 
    } else { 

     button2Oulet.backgroundColor = UIColor.red 
    } 

    if collectionAnswers[2] == 1 { 

     button3Oulet.backgroundColor = UIColor.green 
    } else { 

     button3Oulet.backgroundColor = UIColor.red 
    } 

到目前为止，我已经来了下一个代码，但我可以“T使其工作

可以请你帮我,,,这里

样的卡

for (index,element) in collectionAnswers.enumerated() { 

     switch index { 
     case 0, 1, 2: 
      if element == 0 {print("Bad")} 
      else { 

       for button in collectionOfButtons { 

        if index == button.tag && element == 1 { 

         button.backgroundColor = UIColor.green 

        } else { 

         button.backgroundColor = UIColor.red 
        } 
       } 

       print("OK") 
      } 
     default: 
      break 
     } 
    } 

感谢您的帮助！

Answer 1

长话短说，创建一个包含按钮OU（T）的附加阵列允许

let collectionAnswers = [0, 0, 1] 
let buttons = [button1Oulet, button2Oulet, button3Oulet] 

for (index, answer) in collectionAnswers.enumerated() { 
    buttons[index].backgroundColor = (answer == 0) ? .red : .green 
}