XSLT CONCAT字符串

我有下面的XMLXSLT CONCAT字符串

<R N="14" MIME="application/pdf"> 
     <RK>7</RK> 
     <FS NAME="date" VALUE="2007-11-01" /> 
     <MT N="Abstract" V="Lorem Ipsum is simply dummy text of the printing " /> 
     <MT N="Abstract1" V="and typesetting industry. Lorem Ipsum has been the industry's standard " /> 
     <MT N="Abstract2" V="dummy text ever since the 1500s, when an unknown printer took a galley" /> 
     <MT N="CreationDate" V="D:20070730173554+05'30'" /> 
     <MT N="Creator" V="PageMaker 6.5" /> 
     <MT N="Producer" V="Acrobat Distiller 8.0.0 (Windows)" /> 
     <MT N="ModDate" V="D:20071024091122+05'30'" /> 
     <S> 
      <b>...</b> handling/storage. Operational reactor physics plays an important role in<br/> 
      efficient, smooth and safe operation of <b>nuclear reactor</b>. In <b>...</b> 
     </S> 
     <LANG>en</LANG> 
    </R>

使用XSLT，我需要连接摘要，Abstract1，Abstract2，Abstract3值......等等。

我的XSLT是这样

<xsl:template match="R"> 
    <xsl:choose> 
     <xsl:when test="MT[@N = 'Abstract' and @V != '']"> 
      <xsl:call-template name="reformat_keyword"> 
       <xsl:with-param name="orig_string" select="concat(MT[@N='Abstract']/@V,MT[@N='Abstract1']/@V,MT[@N='Abstract2']/@V)" /> 
      </xsl:call-template> 
     </xsl:when> 
     <xsl:otherwise> 
      <xsl:if test="$show_res_snippet != '0'"> 
       <xsl:call-template name="reformat_keyword"> 
        <xsl:with-param name="orig_string" select="S" /> 
       </xsl:call-template> 
      </xsl:if> 
     </xsl:otherwise> 
    </xsl:choose> 
</xsl:template>

取而代之的是静态的级联，我需要一个通用的功能。

来源

2011-03-02 itsbalur

可能重复http://stackoverflow.com/questions/5168867/ XSLT改造，串连接） – 2011-03-02 16:05:50

如果我得到你的权利，你可以这样做

<xsl:variable name="con-cats"><xsl:apply-templates 
    select="MT[starts-with(@N,'Abstract')]" 
    mode="concatthem"/></xsl:variable>

别处：

<xsl:template match="MT" mode="concatthem"> 
<xsl:value-of select="@V"/> 
</xsl:template> 
<xsl:template match="*|text()" mode="concatthem" />

（没有测试过，可能有错误）。

来源

2011-03-02 09:49:07

我估摸这个问题是如何选择其中属性具有非恒定值... – rene 2011-03-02 09:57:12

thanks.Its关闭节点。它连接了MT下的所有字符串。我需要选择性拼接只有抽象的，Abstract1，Abstract2 ..等。其最好的，如果这个可以进行通用的。这意味着，现在它是抽象的，后来可能是Creator1，Creator2等 – itsbalur 2011-03-02 10:00:05

啊。那么，你可以选择'MT [开始，用（@ N“摘要”）]'，选择部分只是一个例子。 – 2011-03-02 10:12:37

在XSLT 2.0，这是

<xsl:variable name="answer" 
    select="string-join(MT[starts-with(@N, 'Abstract']/@V, '')"/>

在XSLT 1.0，这是

<xsl:variable name="answer"> 
    <xsl:for-each select="MT[starts-with(@N, 'Abstract']"> 
    <xsl:value-of select="@V"/> 
    </xsl:for-each> 
</xsl:variable>

[XSLT转换，字符串连接（的

来源

2011-03-02 11:51:34

XSLT CONCAT字符串

回答

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