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Question

我想临时让logging.warning调用引发异常，而不是打印并继续。我怎样才能做到这一点？

import logging 
logging.warning("Foo") # Should raise exception 
logging.info("Bar") # Should not raise exception 

Answer 1

当你初始化你的日志改变报警电话

def warning(self, message, *args, **kws): 
    if self.isEnabledFor(logging.WARNING): 
     self._log(logging.WARNING, message, args, **kws) 
     raise Exception(message) 

logging.Logger.warning = warning