有问题与MySQL中

有查询

我试图做到这一点查询：有问题与MySQL中

SELECT *, (6371 * acos(cos(radians(43.656906)) * cos(radians(latitude)) * cos(radians(longitude) - radians(-79.434356)) + sin(radians(43.656906)) * sin(radians(latitude)))) AS distance FROM Locations HAVING distance < 10 AND HAVING category='%Family%'

但我得到这个错误：

#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'HAVING category='%Family%' LIMIT 0, 30' at line 1

有谁知道是什么问题？

来源

2014-11-09 Jean-Mathieu

删除第二个'having'过滤 – 2014-11-09 07:18:24

我需要它有它为我的结果笑...... – 2014-11-09 07:19:12

我的意思是删除'having'仅剩下的应该留样'和类别=“％家庭％”' – 2014-11-09 07:20:23

我希望类是列在表

SELECT *, (6371 * acos(cos(radians(43.656906)) * cos(radians(latitude)) * cos(radians(longitude) - radians(-79.434356)) + sin(radians(43.656906)) * sin(radians(latitude)))) AS distance FROM Locations where category like '%Family%' HAVING distance < 10

来源

2014-11-09 07:27:51

由于它的工作。 – 2014-11-09 07:31:33

接受的答案，然后 – 2014-11-09 07:32:18

您需要删除第二HAVING，只需使用AND来告诉MySQL，这两个条件必须成立。

SELECT *, (6371 * acos(cos(radians(43.656906)) * cos(radians(latitude)) * cos(radians(longitude) - radians(-79.434356)) + sin(radians(43.656906)) * sin(radians(latitude)))) AS distance FROM Locations HAVING distance < 10 AND category='%Family%'

来源

2014-11-09 07:24:43

不能添加具有两倍的条件。你可以用“和”“具有” condition.So里面的代码将是：

SELECT *, (6371 * acos(cos(radians(43.656906)) * cos(radians(latitude)) * cos(radians(longitude) - radians(-79.434356)) + sin(radians(43.656906)) * sin(radians(latitude)))) AS distance FROM Locations HAVING distance < 10 AND category='%Family%'

来源

2014-11-09 07:33:20

有问题与MySQL中

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