或声明无效语法

Question

所以，我的一个朋友告诉我或声明，但是当我使用它，它说无效的语法......但不会告诉我在哪里

#Fun Game 

print("Enter name") 

firstname = input() 

print ("Thousands of years further from our time, the continents collided, creating mass devastation and heat.You,"+firstname+" lived in a peacful village until") 

print (" your village was raided by four men, everyone else died other than you, who was trained as an assasin and killed them all") 

age1 = input ("you,"+firstname+" as a 16 year old killed them all and escaped into a cave. Now that cave is what you call home.Enter your character's current age(max 25 min 20) ") 

if age1 == "20": 
    print("") 

or age1 == "21": 
    print("") 

or age1 == "22": 
    print ("") 

or age1 == "23": 
    print ("") 

or age1 == "24": 
    print ("") 

or age1 == "25": 
    print("") 

else: 
    print ("Choose an age in the list") 

cave1 = input ("You can do 2 things:") 

print ("1.Go to your friend's village(700 people,military grade)and trade,look for bountys and find news") 

Answer 1

Poonam的答案看起来不错，但你可能也不想很多if语句：

print("Enter name") 

firstname = input() 

print ("Thousands of years further from our time, the continents collided, creating mass devastation and heat.You,"+firstname+" lived in a peacful village until") 

print (" your village was raided by four men, everyone else died other than you, who was trained as an assasin and killed them all") 

age1 = input ("you,"+firstname+" as a 16 year old killed them all and escaped into a cave. Now that cave is what you call home.Enter your character's current age(max 25 min 20) ") 

if age1 in ["20","21","22","23","24","25"]: 
    print("") 
else: 
    print ("Choose an age in the list") 

cave1 = input ("You can do 2 things:") 

print ("1.Go to your friend's village(700 people,military grade)and trade,look for bountys and find news") 

Answer 2

print("Enter name") 

firstname = input() 

print ("Thousands of years further from our time, the continents collided, creating mass devastation and heat.You,"+firstname+" lived in a peacful village until") 

print (" your village was raided by four men, everyone else died other than you, who was trained as an assasin and killed them all") 

age1 = input ("you,"+firstname+" as a 16 year old killed them all and escaped into a cave. Now that cave is what you call home.Enter your character's current age(max 25 min 20) ") 

if age1 == "20": print("") 

elif age1 == "21": print("") 

elif age1 == "22": print ("") 

elif age1 == "23": print ("") 

elif age1 == "24": print ("") 

elif age1 == "25": print("") 

else: print ("Choose an age in the list") 

cave1 = input ("You can do 2 things:") 

print ("1.Go to your friend's village(700 people,military grade)and trade,look for bountys and find news") 

Answer 3

当你使用'或'运算符，将其用作条件的一部分。 例如：

if x == 1 or x == 5: 
    print(x) 

所以，你的代码将是一个长行，没有所有的print语句：

if age1 == "20" or age1 == "21" or age1 == "22" or age1 == "23" or age1 == "24" or age1 == "25": 
    print("") 

从你的代码，我想你想要的是一个elif的语句：

if age1 == "20": 
    ##Do something based on input of 20 
elif age1 == "21": 
    ##Do something else if input is 21 
elif age1 == "22": 
    ##Something else again if input is 22 
else: 
    ##Do something if the age is not captured above. 

如果您需要两个或更多条件中的一个为真，则只需使用“或”运算符。但是，如果你只是想检查，如果输入年龄的范围内尝试这个办法：

if inval >= 20 and inval <= 25: 
    print("Correct Value") 
else: 
    print("Incorrect value") 

或者，使用范围：

if inval in range(20, 26): 
    print("Correct Value") 
else: 
    print("Incorrect value")