我遇到一个比较奇怪的问题。断言在脚本中无效,但类型比较在终端中工作
我想解码python脚本参数,存储并分析它们。在以下命令中,应使用-r选项来确定要创建哪种类型的报告。
python脚本启动: %run decodage_parametres_script.py -r junit,html
python脚本选项解析用于填充字典,结果是: current_options:
{'-cli-no-summary': False, '-cli-silent': False, '-r': ['junit', 'html']}
然后我要测试的-r选项,这里是代码:
for i in current_options['-r']:
# for each reporter required with the -r option:
# - check that a file path has been configured (otherwise set default)
# - create the file and initialize fields
print("trace i", i)
print("trace current_options['-r'] = ", current_options['-r'])
print("trace current_options['-r'][0] = ", current_options['-r'][0])
if current_options['-r'][i] == 'junit':
# request for a xml report file
print("request xml export")
try:
xml_file_path = current_option['--reporter-junit-export']
print("xml file path = ", xml_file_path)
except:
# missing file configuration
print("xml option - missing file path information")
timestamp = get_timestamp()
xml_file_path = 'default_report' + '_' + timestamp + '.xml'
print("xml file path = ", xml_file_path)
if xml_file_path is not None:
touch(xml_file_path)
print("xml file path = ", xml_file_path)
else:
print('ERROR: Empty --reporter-junit-export path')
sys.exit(0)
else:
print("no xml file required")
I想试试默认的报表生成,但我甚至不打打印(“请求XML导出”)线,这里是控制台结果:
trace i junit
trace current_options['-r'] = ['junit', 'html']
trace current_options['-r'][0] = junit
正如我想这可能是一个类型的问题,我试着以下测试:
In [557]: for i in current_options['-r']:
...: print(i, type(i))
...:
junit <class 'str'>
html <class 'str'>
In [558]: toto = 'junit'
In [559]: type(toto)
Out[559]: str
In [560]: toto
Out[560]: 'junit'
In [561]: toto == current_options['-r'][0]
Out[561]: True
所以我行断言if current_options['-r'][i] == 'junit'
:应该结束了开始真实的,但它并非如此。 我错过了一些微不足道的事吗? :(
有人可以帮助我,请
非常感谢,它的工作原理:)我没看出来,尽管我的照片。我将使用解决方案1;) –