比较2个数组

Question

是否有函数比较2个不同的关联数组，并返回更改？

例如

$age = array("Peter"=>"35","Ben"=>"37","Joe"=>""); 
$age2 = array("Peter"=>"38","Ben"=>"37","Joe"=>"43"); 

回报

$return = array(
    "Peter"=>"Changed from 35 to 38", 
    "Joe"=>"Changed from blank to 43" 
); 

Answer 1

正如前面所指出的，array_diff_assoc是你的出发点。其余的正在建设的字符串每个区别：

function compareAge($age, $age2) 
{ 
    $return = array(); 
    foreach(array_keys(array_diff_assoc($age, $age2)) as $diffKey) { 
     $from = empty($age[$diffKey]) ? 'blank' : $age[$diffKey]; 
     $to = empty($age2[$diffKey]) ? 'blank' : $age2[$diffKey]; 
     $return[$diffKey] = "Changed from {$from} to {$to}"; 
    } 
    return $return; 
} 

working demo

Answer 2

array_diff可以在正确的道路上开始你。尽管它没有提供你正在寻找的确切输出，但它会显示两个数组之间的差异。

正如标记指出的那样，array_diff_assoc可能更有帮助，因为它维护数组索引。

Answer 3

没有默认情况下，我有我的手一段时间:) http://codepad.org/2UtrPE3o

<? 
$age = array("Peter"=>"35","Ben"=>"37","Joe"=>""); 
$age2 = array("Peter"=>"38","Ben"=>"37","Joe"=>"43"); 

$result = array(); 
foreach($age as $key=>$val) { 
    if (array_key_exists($key, $age2)) { 
    if ($val!==$age2[$key]) 
     $result[$key] = 'Changed from '.(empty($val)?'blank':$val).' to '. (empty($age2[$key])?'blank':$age2[$key]); 
    } else { 
    $result[$key] = 'Changed from '.(empty($val)?'blank':$val).' to blank'; 
    } 
} 

foreach($age2 as $key=>$val) { 
    if (!array_key_exists($key, $age)) { 
    $result[$key] = 'Changed from blank to ' . $val; 
    } 
} 

var_dump($result); 
?> 

Answer 4

检查这一点，更有效的解决方案：

$age1 = array("Peter"=>"35","Ben"=>"37","Joe"=>""); 
$age2 = array("Peter"=>"38","Ben"=>"37","Joe"=>"43"); 

$result = array_diff_assoc($age1, $age2); 

$res = array(); 
foreach($result as $key=>$val){ 
    $res[$key] = "Changed from ".($val?$val:"Balnk")." to ".($age2[$key]?$age2[$key]:"blank"); 
} 

echo "<pre>"; 
print_r($res);