在获取错误和登录时重复CURL代码php

Question

当curl_error为true并且如果仍然失败，请在错误日志中输入时，我想保持此代码循环（两次/三次）。

$ch = curl_init($api_url); 
    curl_setopt($ch, CURLOPT_CUSTOMREQUEST, "POST"); 
    curl_setopt($ch, CURLOPT_RETURNTRANSFER, true); 
    curl_setopt($ch, CURLOPT_POSTFIELDS, http_build_query($post)); 
    curl_setopt($ch, CURLOPT_HTTPHEADER, array('Content-Type: application/x-www-form-urlencoded')); 

$response = curl_exec($ch); 

/* if there is an error show error */ 
if (curl_error($ch) && curl_getinfo($ch, CURLINFO_HTTP_CODE) != 200) { 
    $success = false; 
    return view('frontend.user.rss', compact('project_detail_all','active_project_detail','rss_detail','success')); 
} 
curl_close($ch); 

请给出您的建议，谢谢。

Answer 1

我没有做很多curl荷兰国际集团，但是这似乎是一个合乎逻辑的方式...

$i=0; 
do{ 
    $ch = curl_init($api_url); 
     curl_setopt($ch, CURLOPT_CUSTOMREQUEST, "POST"); 
     curl_setopt($ch, CURLOPT_RETURNTRANSFER, true); 
     curl_setopt($ch, CURLOPT_POSTFIELDS, http_build_query($post)); 
     curl_setopt($ch, CURLOPT_HTTPHEADER, array('Content-Type: application/x-www-form-urlencoded')); 

    $response = curl_exec($ch); 

    /* if there is an error show error */ 
    if(curl_error($ch) && curl_getinfo($ch, CURLINFO_HTTP_CODE)!=200){ 
     $success=false; 
    }else{ 
     $success=true; 
     break; 
    } 
    curl_close($ch); 
    ++$i; 
}while($i<3); 

if($success){ 
    // return what you want/$response 
}else{ 
    // log the failure, return what you want 
    // return view('frontend.user.rss', compact('project_detail_all','active_project_detail','rss_detail','success')); 
}