2016-08-23 83 views
1

我正在构建一个脚本,将比较最后一次使用中的IPv4地址与所有可用的操作(从2到254)。变量中的比较对象输出

我已经到目前为止,我通过比较数组得到了一个结果,但我的最终结果也是一个数组,我似乎无法得到唯一的数字。

我的脚本:

$guestIP = @("192.168.31.200","192.168.31.31","192.168.31.90","192.168.31.25","192.168.31.100") 

$AllLastOcted = $("2","3","4","5","6","7","8","9","10","11","12","13","14","15","16","17","18","19","20","21","22","23","24","25","26","27","28","29","30","31","32","33","34","35","36","37","38","39","40","41","42","43","44","45","46","47","48","49","50","51","52","53","54","55","56","57","58","59","60","61","62","63","64","65","66","67","68","69","70","71","72","73","74","75","76","77","78","79","80","81","82","83","84","85","86","87","88","89","90","91","92","93","94","95","96","97","98","99","100","101","102","103","104","105","106","107","108","109","110","111","112","113","114","115","116","117","118","119","120","121","122","123","124","125","126","127","128","129","130","131","132","133","134","135","136","137","138","139","140","141","142","143","144","145","146","147","148","149","150","151","152","153","154","155","156","157","158","159","160","161","162","163","164","165","166","167","168","169","170","171","172","173","174","175","176","177","178","179","180","181","182","183","184","185","186","187","188","189","190","191","192","193","194","195","196","197","198","199","200","201","202","203","204","205","206","207","208","209","210","211","212","213","214","215","216","217","218","219","220","221","222","223","224","225","226","227","228","229","230","231","232","233","234","235","236","237","238","239","240","241","242","243","244","245","246","247","248","249","250","251","252","253","254") 

$guestIP = $guestIP | sort -Property {$_-replace '[\d]'},{$_-replace '[a-zA-Z\p{P}]'-as [int]} 
$AllLastOcted = $AllLastOcted | sort -Property {$_-replace '[\d]'},{$_-replace '[a-zA-Z\p{P}]'-as [int]} 

$guestIP = $guestIP -replace('192.168.31.','') 

Compare-Object -ReferenceObject ($AllLastOcted) -DifferenceObject ($guestIP) | select -Property InputObject -First 1 | set-Variable AvailableOcted -PassThru 

$AvailableOcted 

我的目标是,是,我有作为导致第一可用octed,我可以使用。 像:

write-host "IP that can be used is 192.168.31.$AvailableOcted" 
PS > IP that can used is 192.168.31.2 
+0

使用-ExpandProperty代替,物业在对您的选择,Statement对象结束。 –

回答

1

可以简化这个有很多。

您可以使用范围运算符来创建数组,而不是定义2到254中的所有数字。你也不需要[int]演员。除了使用Compare-Object cmdlet来过滤octeds的,你可以使用Where-Object的cmdlet:

$guestIP = @("192.168.31.200","192.168.31.31","192.168.31.90","192.168.31.25","192.168.31.100") 

$AllLastOcted = 2 .. 254 
$usedOcted = $guestIP -replace '.*\.' 
$nextAvailableOcted = $AllLastOcted | Where { $_ -NotIn $usedOcted } | select -first 1 

write-host "IP that can be used is 192.168.31.$nextAvailableOcted" 

输出:

IP that can be used is 192.168.31.2 
+1

该死的是realy简化..非常感谢...使这个剧本花了我很多时间:))...仍在学习powershell。 –

+0

不客气。继续! –

1

嗯,就这么简单:

$AvailableOcted.InputObject 

将只返回值。

因此,这将是这样的:

write-host ("IP that can be used is 192.168.31." + $AvailableOcted.InputObject)