2017-04-27 75 views
0

执行多个查询在第一选择查询,如果id存在只是更新量在我的情况下,否则执行insert(id, quantity)查询 刚刚更新查询执行PHP PDO环路

$fodid = $data->orfid; 
$quantity = $data->orqnt; 

include('db.php');  

try{        
    $sqlchk="SELECT `orfoodid` AS FROM `orders` where `orfoodid`=':chkfoodid';"; 
    $sqlupdate="UPDATE `resturant`.`orders` SET `orfoodqnt` = ':chcount' WHERE `orders`.`orfoodid` = ':chfodid';"; 
    $sql="INSERT INTO `resturant`.`orders` (`orfoodid`, `orfoodqnt`) VALUES (:foodid,:count);"; 

    for($i=0;$i<sizeof($fodid);$i++){ 

     $rs = $conn->prepare($sqlchk); 
     $rs->execute(array(':chkfoodid'=>$fodid[$i]));  
     $result=$rs->fetch(PDO::FETCH_ASSOC);  

     if(!$result) 
     { 
      $rs = $conn->prepare($sqlupdate); 
      $rs->execute(array(':chfodid'=>$fodid[$i], 
          ':chcount'=>$quantity[$i])); 
      echo 'Order updated';      
     } else {   
      $rs = $conn->prepare($sql); 
      $rs->execute(array(':foodid'=>$fodid[$i], 
          ':count'=>$quantity[$i])); 
      echo 'Order Saved'; 
     }   

    }       
    $conn=null; 
}catch (PDOException $e) { 
    print "Error!: " . $e->getMessage() . "<br/>"; 
    die(); 
} 
+0

只是一个说明:一个声明只能一次准备。因此,准备一次,并给所有stmts和可读的名称,如'$ selectStmt' – JustOnUnderMillions

+0

你的混凝土问题在哪里? – JustOnUnderMillions

+0

另一个说明,请使用['insert on duplicate update'](https://dev.mysql.com/doc/refman/5.7/en/insert-on-duplicate.html)声明 – hassan

回答

0

我解决我的问题是语法错误 “: chkfoodid'只是删除单引号:chkfoodid