我正在尝试将一些第三方跟踪代码集成到我的网站之一,但它是抛出一些错误,并且他们的支持没有多大用处,所以我想要尝试自己修复他们的代码。最让我有固定的,但是这个功能是给我的问题:X转发 - 为PHP中导致未定义的索引
private function getXForwardedFor()
{
$s =& $this;
$xff_ips = array();
$headers = $s->getHTTPHeaders();
if ($headers['X-Forwarded-For']) {
$xff_ips[] = $headers['X-Forwarded-For'];
}
if ($_SERVER['REMOTE_ADDR']) {
$xff_ips[] = $_SERVER['REMOTE_ADDR'];
}
return implode(', ', $xff_ips); // will return blank if not on a web server
}
在我的开发环境在那里我显示所有的错误我得到:1129
Notice: Undefined index: X-Forwarded-For in /sites/webs/includes/OmnitureMeasurement.class.php on line 1129
线路是:
if ($headers['X-Forwarded-For']) {
如果我打印出$标题,我会得到:
Array
(
[Host] => www.domain.com
[User-Agent] => Mozilla/5.0 (Windows; U; Windows NT 6.1; en-GB; rv:1.9.2.3) Gecko/20100401 Firefox/3.6.3
[Accept] => text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8
[Accept-Language] => en-gb,en;q=0.5
[Accept-Encoding] => gzip,deflate
[Accept-Charset] => ISO-8859-1,utf-8;q=0.7,*;q=0.7
[Keep-Alive] => 115
[Connection] => keep-alive
[Referer] => http://www10.toptable.com/
[Cookie] => PHPSESSID=nh9jd1ianmr4jon2rr7lo0g553; __utmb=134653559.30.10.1275901644; __utmc=134653559
[Cache-Control] => max-age=0
)
我看不到X-Forwarded-For在那里,我认为是造成问题。有什么我应该添加到功能考虑到这一点?
我在Fedora
和再见错误消息。非常感谢。 (只要它让我接受!) – 2010-06-07 13:22:51