搜索字符串在一个字符串

Question

亲爱的计算器成员，

我有这个字符串：

string data = "1Position1234Article4321Quantity2Position4323Article3323Quantity"; 

我想搜索其中“关键词”是位置的值。在这种情况下，我想回到1和2.每个值都是用自己的“关键字”“索引”的。所以这个字符串中的值1有位置分隔符。值1234具有文章分隔符，值4321具有数量分隔符。

我需要一种方法来搜索字符串，并希望获取所有位置，文章和数量。没有关键字。

输出喊是：

string[] position = {"1", "2"}; 
string[] article = {"1234", "4323"}; 
string[] quantity = {"4321", "3323"}; 

希望一些可以帮助我在这里。

谢谢！

Answer 1

这为q快速的解决方案，我在LinqPad想出了：

void Main() 
{ 
     string data = "1Position1234Article4321Quantity2Position4323Article3323Quantity"; 
     var Articles = Indices(data, "Article").Dump("Articles: "); 
     var Posistions = Indices(data, "Position").Dump("Positions :"); 
     var Quantities = Indices(data, "Quantity").Dump("Quantities :"); 
} 

// Define other methods and classes here 
public List<int> Indices(string source, string keyword) 
{ 
    var results = new List<int>(); 
    //source: http://stackoverflow.com/questions/3720012/regular-expression-to-split-string-and-number 
    var temp = Regex.Split(source, "(?<Alpha>[a-zA-Z]*)(?<Numeric>[0-9]*)").ToList().Where (r => !String.IsNullOrEmpty(r)).ToList(); 
    //select the list with index only where key word matches 
    var indices = temp.Select ((v,i) => new {index = i, value = v}) 
         .Where (t => t.value == keyword); 
    foreach (var element in indices) 
    { 
     int val; 
     //get previous list entry based on index and parse it 
     if(Int32.TryParse(temp[element.index -1], out val)) 
     { 
      results.Add(val); 
     } 
    } 
    return results; 
} 

输出：

Answer 2

这里是一个可能的算法：

• 运行槽名单，并采取每个号码/关键字。
• 将它们放在带有关键字“keyword”的字典中，用所有“数字”列出一个列表。
• 迭代字典并打印它们的键+其值。

Answer 3

下面片段可用于获取输出像你所期望的。

string data = "1Position1234Article4321Quantity2Position4323Article3323Quantity"; 

StringBuilder sb = new StringBuilder(); 
StringBuilder sbWord = new StringBuilder(); 
bool isDigit = false; 
bool isChar = false; 
Dictionary<int, string> dic = new Dictionary<int, string>(); 
int index = 0; 

for (int i = 0; i < data.Length; i++) 
{ 
    if (char.IsNumber(data[i])) 
    { 
    isDigit = true; 
    if (isChar) 
     { 
     dic.Add(index, sb.ToString() + "|" + sbWord.ToString()); 
     index++; 
     isChar = false; 
     sb.Remove(0, sb.Length); 
     sbWord.Remove(0, sbWord.Length); 
     } 

    } 
    else 
      { 
       isDigit = false; 
       isChar = true; 
       sbWord.Append(data[i]); 
      } 

      if (isDigit) 
       sb.Append(data[i]); 

      if (i == data.Length - 1) 
      { 
       dic.Add(index, sb.ToString() + "|" + sbWord.ToString()); 
      } 
     } 

     List<string> Position = new List<string>(); 
     List<string> Article = new List<string>(); 
     List<string> Quantity = new List<string>(); 

     if (dic.Count > 0) 
     { 
      for (int i = 0; i < dic.Count; i++) 
      { 
       if (dic[i].Split('|')[1] == "Position") 
        Position.Add(dic[i].Split('|')[0]); 


       else if (dic[i].Split('|')[1] == "Article") 

        Article.Add(dic[i].Split('|')[0]); 

       else 
        Quantity.Add(dic[i].Split('|')[0]); 
      } 
     } 

     string[] Position_array = Position.ToArray(); 
     string[] Article_array = Article.ToArray(); 
     string[] Quantity_array = Quantity.ToArray(); 

Answer 4

试试这个简单的解决方案。

class StrSplit{ 
    public static void main(String args[]){ 

    int i; 
    String str = "1Position1234Article4321Quantity2Position4323Article3323Quantity"; 
    String pattern= "(?<=Position)|(?<=Article)|(?<=Quantity)"; 

    String[] parts = str.split(pattern); 
    List<String> Position = new ArrayList<String>(); 
    List<String> Article = new ArrayList<String>(); 
    List<String> Quantity = new ArrayList<String>(); 

    for(i=0;i<parts.length;i++) 
    { 
      pattern="Position"; 
      String[] subParts; 
      if(parts[i].contains(pattern)) 
      { 
       subParts = parts[i].split(pattern); 
       Position.add(subParts[0]); 
      } 
      pattern="Article"; 
      if(parts[i].contains(pattern)) 
      { 
        subParts = parts[i].split(pattern); 
        Article.add(subParts[0]); 
      } 
      pattern="Quantity"; 
      if(parts[i].contains(pattern)) 
      { 
        subParts = parts[i].split(pattern); 
        Quantity.add(subParts[0]); 
      } 

    } 
    System.out.println("Position:"); 
    for(i = 0; i < Position.size(); i++) { 
     System.out.println(Position.get(i)); 
    } 
    System.out.println("Article:"); 
    for(i = 0; i < Article.size(); i++) { 
     System.out.println(Article.get(i)); 
    } 
    System.out.println("Quantity:"); 
for(i = 0; i < Quantity.size(); i++) { 
     System.out.println(Quantity.get(i)); 
    } 
} 
} 

输出：
Position: 1 2 Article: 1234 4323 Quantity: 4321 3323