Yii2 - 在模型中提交时如何从Widget获取数据？

Question

我正在使用一个小工具来裁剪和上传图像到Yii2服务器。
Yii2 - Cropper

我实现了在视图中的小部件，基于控件的文档，并submited的数据模型至极应该上传的文件名保存到数据库中的一个新条目。但是，它始终将其保存为Null。

newform.php

<?php 
    use yii\helpers\Html; 
    use yii\widgets\ActiveForm; 
    use common\budyaga\cropper\Widget; 
    use yii\helpers\Url; 
    $this->title='Upload New'; 
?> 
<h1><?= Html::encode($this->title) ?></h1> 
<?php $form = ActiveForm::begin(); ?> 
<?= $form->field($model, 'title') -> textInput();?> 
<?= $form->field($model, 'description') -> textInput(); ?> 
<?= $form->field($model, 'link') -> textInput(); ?> 
<?= $form->field($model, 'image')-> widget(Widget::className(), [ 
    'uploadUrl' => Url::toRoute('/admin/uploadPhoto'), 
    'width' => 236, 
    'height' => 234, 
    'cropAreaWidth' => 500, 
    'cropAreaHeight' => 500, 
    'thumbnailWidth' => 236, 
    'thumbnailHeight' => 234, 
    ]);?> 
<div class="form-group"> 
    <?= Html::submitButton('Save', ['class' => 'btn btn-primary']); ?> 
</div> 
<?php ActiveForm::end(); ?> 

在控制器方法

public function actionNews(){ 
    $model = new NewsForm(); 
    $model->setScenario('addNew'); 
    if ($model->load(Yii::$app->request->post()) && $model->addNew()) { 
     return $this->render('newsmanager'); 
    } else { 
     return $this->render('newform', ['model' => $model]); 
    } 
} 

模型

class Newnews extends \yii\db\ActiveRecord{ 
    public static function tableName() 
    { 
     return 'news'; 
    } 

    public function rules() 
    { 
     return [ 
      [['visits', 'user_id'], 'integer'], 
      [['user_id'], 'required'], 
      [['title', 'image'], 'string', 'max' => 45], 
      [['description', 'link'], 'string', 'max' => 255], 
      [['user_id'], 'exist', 'skipOnError' => true, 'targetClass' => User::className(), 'targetAttribute' => ['user_id' => 'id']], 
     ]; 
    } 

    public function attributeLabels() 
    { 
     return [ 
      'idnew' => 'Idnew', 
      'title' => 'Title', 
      'description' => 'Description', 
      'image' => 'Image', 
      'visits' => 'Visits', 
      'user_id' => 'User_ID', 
      'link' => 'Link', 
      'dateu' => 'Dateu' 
     ]; 
    } 
} 

NewsForm.php

class NewsForm extends Model 
{ 
    public $image; 
    public $title; 
    public $description; 
    public $link; 

    public function rules() 
    { 
     return [ 
      [['title','description','link'],'required'], 
      ['image','safe', 'on'=>'addNew'] 
     ]; 
    } 

    public function addNew(){ 
     if($this->validate()){ 
      $newnew=new Newnew(); 
      $newnew->title=$this->title; 
      $newnew->description=$this->description; 
      $newnew->link=$this->link; 
      $newnew->image; 
      $newnew->user_id=Yii::$app->getUser()->getId(); 
      $newnew->visits=0; 
      $newnew->dateu=date("Y-m-d H:i:s"); 
      return $newnew->save(); 
     } 
    } 
} 

当我尝试保存数据，我得到了图像的空。我不知道如何从wiget获取数据以提取模型中图像的名称。我如何访问这些数据？

Answer 1

加入NewsForm：

/** 
* @var UploadedFile 
*/ 
public $imageFile; 

和在验证规则：

[['imageFile'], 'file', 'mimeTypes' => 'image/jpeg, image/png', 'maxSize' => 5000000], 

在ADDNEW（）函数：

$this->imageFile = UploadedFile::getInstance($this, 'imageFile'); 
$file = $this->imageFile; 
$fname = $file->baseName 
$fext = $file->extension 
//etc... 
//then validate and save file and model as you want. 

在视图形式：

<?= $form->field($model, 'imageFile ')-> widget(Widget::className(), [ 
//config... 
]);