获取网址的具体参数

网址为http://www.test.co.uk/?set_cp_city=thecity，通常我可以使用$_GET['set_cp_city']但这不起作用。也许与wordpress有关。那么，如何获得价值参数set_cp_city获取网址的具体参数

Here'ss我的代码

<select onChange="window.location.href=this.value"> 
<?php 
$locations = array("London","Bristol","Manchester","Kent","Essex","Lancashire","Bedfordshire","Berkshire","Buckinghamshire","Cambridgeshire","Cheshire","Cornwall","County Durham","Cumbria","Derbyshire","Devon","Dorset","East Yorkshire","East Sussex","Gloucestershire","Hampshire","Herefordshire","Hertfordshire","Isle of Wight","Leicestershire","Lincolnshire","Merseyside","Norfolk","North Yorkshire","Northamptonshire","Northumberland","Nottinghamshire","Oxfordshire","Rutland","Shropshire","Somerset","South Yorkshire","Staffordshire","Suffolk","Surrey","Tyne and Wear","Warwickshire","West Midlands","West Sussex","West Yorkshire","Wiltshire","Worcestershire"); 
$current_city = $_GET['set_cp_city']; 


echo "<option>$current_city</option>"; 

foreach($locations as $value) { 
?> 
<option value="http://www.test.co.uk/?set_cp_city=<?php echo $value ?>"><?php echo $value ?></option> 
<?php 
} 

?> 
</select>

来源

2014-11-06 user892134

检查你的'.htaccess'，看看是否内部存在'[QSA]'。如果不行，你可能需要在'ReWrite *'行之后添加它。 – Gary 2014-11-06 11:07:12

$_SERVER['QUERY_STRING']应包含请求的查询，并且可以使用parse_str()它

parse_str($_SERVER['QUERY_STRING'],$output); 
print_r($output);

来源

2014-11-06 11:04:58 dynamic

什么是$输出？我试过这个，结果是'1' – user892134 2014-11-06 11:12:20

试图回显$ _SERVER ['QUERY_STRING']，看看它是否包含你的参数 – dynamic 2014-11-06 11:13:42

兄弟我想你需要设置值'$ data = parse_url（'url'）'。该语法用于'parse_str（'query_string'，$ return_Value）'。但无论如何，我不知道这是否仍然有效，很奇怪，'$ _GET' aint workin – Ghost 2014-11-06 11:17:56

试这在你的代码

$current_city = isset($_GET['set_cp_city'])?$_GET['set_cp_city']:"";

来源

2014-11-06 12:02:50

获取网址的具体参数

回答

相关问题