2016-03-03 107 views
0

时有什么不对下面的步骤我收到以下错误PLS-00103:出现符号 “(” 期待

LINE/COL ERROR


1/107? PLS-00103:出现符号 “(” 期待的 的 下列之一时: :=),@%默认字符 符号 “:=” 代替 “(” 继续

1/114 PLS-00103:出现符号 “IS” 期待的 的 一个以下时: 回报

CREATE OR REPLACE FUNCTION MOBLIE_RX_VERIFICATION(ARG_DAD_ID IN NUMBER,ARG_PATIENT_NAME IN VARCHAR2,ARG_VERIFY_MODE VARCHAR2(15)) AS 

DECLARE 

NEW_CCH_ID NUMBER; 
CCH_COUNT NUMBER; 
CCL_COUNT NUMBER; 
vPAT_ID VARCHAR2(20); 
vENCNTR_ID NUMBER; 
vSTM_ID NUMBER; 
vADMIN_DT DATE; 
vGIM_ID NUMBER; 
vIDM_ID NUMBER; 
vQTY NUMBER; 
vUOM_ID NUMBER; 
vMEDIUM_IDM NUMBER; 
vMEDIUM_QTY NUMBER; 
vMEDIUM_UOM NUMBER; 
vMEDIUM_GIM NUMBER; 
vPPD_ID NUMBER; 
vADMIN_TYPE VARCHAR2(50); 
vSTATUS VARCHAR2(50); 
vDOSE VARCHAR2(15); 

BEGIN 

SELECT DAD_PATIENT_ID, DAD_ENCOUNTER_ID, DAD_STM_ID, TRUNC(DAD_ADMIN_DATE), DAD_GIM_ID, DAD_IDM_ID, DAD_QUANTITY, DAD_UOM_ID, NVL(DAD_MEDIUM_IDM_ID,0), DAD_MEDIUM_QTY, DAD_MEDIUM_UOM_ID, NVL(DAD_PPD_ID,0), DAD_ADMIN_TYPE,DAD_STATUS, DAD_DOSE_NUM 
INTO vPAT_ID,vENCNTR_ID,vSTM_ID,vADMIN_DT,vGIM_ID,vIDM_ID,vQTY,vUOM_ID,vMEDIUM_IDM, vMEDIUM_QTY, vMEDIUM_UOM,vPPD_ID,vADMIN_TYPE, vSTATUS,vDOSE 
FROM DRUG_ADMIN_DETAIL 
WHERE DAD_ID = ARG_DAD_ID; 

SELECT COUNT(*) INTO CCH_COUNT FROM CURRENT_CONSUMPTION_HEADER 
WHERE CCH_STM_ID = vSTM_ID AND CCH_CONSUMPTION_TYPE = 'PATIENT' AND TRUNC(CCH_CONSUMPTION_DATE) = vADMIN_DT; 



IF ARG_VERIFY_MODE = 'VERIFY' THEN 


    UPDATE DRUG_ADMIN_DETAIL SET DAD_STATUS= 'VERIFIED' WHERE DAD_ID= ARG_DAD_ID; 

    IF vPPD_ID <> 0 THEN 

     UPDATE PATIENT_PRESCRIPTION_DETAIL SET PPD_STATUS= 'VERIFIED' WHERE PPD_ID= vPPD_ID AND PPD_STATUS= 'ADMINISTERED';  

    END IF; 

    IF CCH_COUNT = 0 THEN 

     INSERT INTO CURRENT_CONSUMPTION_HEADER(CCH_STM_ID, CCH_CONSUMPTION_DATE, CCH_CONSUMPTION_TYPE, CCH_STATUS) 
     VALUES (vSTM_ID, vADMIN_DT, 'PATIENT', 'OUTSTANDING') RETURNING CCH_ID INTO NEW_CCH_ID; 

    ELSE 

     SELECT CCH_ID INTO NEW_CCH_ID FROM CURRENT_CONSUMPTION_HEADER 
     WHERE CCH_STM_ID = vSTM_ID AND CCH_CONSUMPTION_TYPE = 'PATIENT' AND TRUNC(CCH_CONSUMPTION_DATE) = vADMIN_DT; 


    END IF; 

    INSERT INTO CURRENT_CONSUMPTION_LINE (CCL_CCH_ID, CCL_ADMISSION_NO, CCL_PATIENT_ID, CCL_IDM_ID, UOM_ID,CCL_CONS_CATOGORY, 
    CCL_CONS_FACTOR, CCL_QTY, CCL_PATIENT_NAME, CCL_SHIFT,CCL_STATUS, CCL_DAD_ID) 
    VALUES (NEW_CCH_ID,vENCOUNTER_ID, vPATIENT_ID,vIDM_ID,VUOM_ID, (SELECT GIM_CONS_CATEGORY FROM GENERIC_ITEM_MASTER WHERE GIM_ID=vGIM_ID), 
    (SELECT GIM_CONS_FACTOR FROM GENERIC_ITEM_MASTER WHERE GIM_ID=vGIM_ID),vQTY,ARG_PATIENT_NAME,vDOSE,'OUTSTANDING', ARG_DAD_ID);  

    IF vMEDIUM_QTY > 0 

     SELECT IDM_GIM_ID INTO vMEDIUM_GIM 
     FROM ITEM_dETAILS_MASTER 
     WHERE IDM_ID = vMEDIUM_IDM; 

     INSERT INTO CURRENT_CONSUMPTION_LINE (CCL_CCH_ID, CCL_ADMISSION_NO, CCL_PATIENT_ID, CCL_IDM_ID, UOM_ID,CCL_CONS_CATOGORY, 
     CCL_CONS_FACTOR, CCL_QTY, CCL_PATIENT_NAME, CCL_SHIFT) 
     VALUES (NEW_CCH_ID,vENCOUNTER_ID, vPATIENT_ID,vMEDIUM_IDM,vMEDIUM_UOM, (SELECT GIM_CONS_CATEGORY FROM GENERIC_ITEM_MASTER WHERE GIM_ID=vMEDIUM_GIM), 
     (SELECT GIM_CONS_FACTOR FROM GENERIC_ITEM_MASTER WHERE GIM_ID=vMEDIUM_GIM),vMEDIUM_QTY,ARG_PATIENT_NAME,vDOSE,'OUTSTANDING', ARG_DAD_ID); 

    END IF; 


ELSIF ARG_VERIFY_MODE = 'DEVERIFY' THEN 

    UPDATE DRUG_ADMIN_DETAIL SET DAD_STATUS= 'ADMINISTERED' WHERE DAD_ID= ARG_DAD_ID; 

    IF vPPD_ID <> 0 THEN 

     UPDATE PATIENT_PRESCRIPTION_DETAIL SET PPD_STATUS= 'ADMINISTERED' WHERE PPD_ID= vPPD_ID AND PPD_STATUS= 'VERIFIED';  

    END IF; 


    SELECT CCL_CCH_ID INTO NEW_CCH_ID FROM CURRENT_CONSUMPTION_LINE WHERE CCL_DAD_ID = ARG_DAD_ID; 

    DELETE CURRENT_CONSUMPTION_LINE 
    WHERE CCL_DAD_ID = ARG_DAD_ID; 


    DELETE CURRENT_COMSUMPTION_HEADER 
    WHERE CCH_ID = NEW_CCH_ID 
    AND (SELECT COUNT(*) FROM CURRENT_CONSUMPTION_LINE WHERE CCL_CCH_ID = NEW_CCH_ID) = 0; 


END IF; 

COMMIT; 
END; 
+1

参数没有长度。 'arg_verify_mode'应该只是一个'varchar2'。你也不要在存储过程中使用'declare'。 'as'开始你的声明部分。在第一对情侣线后,我停止查找语法错误。 –

+0

请看看它,请修改所需的更改。我没有得到什么问题。@ JustinCave –

+1

你看到你声明'arg_verify_mode'的参数列表吗?你已经包含了一个长度。参数没有长度。删除长度。删除'declare'。除此之外,从小开始建立起来是有道理的。至少这两个语法错误是你的声明。从一个不做任何事情的存储过程开始,并让它进行编译。然后添加代码广告,确保它在每次迭代时编译。这比试图在一百行代码中查找所有语法错误要容易得多。 –

回答

1

您的程序的签名有三个语法错误。

  1. 它没有返回值,因此它是一个过程不是一个函数
  2. 您所指定的第三个参数的长度;这对PL/SQL参数无效。
  3. DECLARE关键字仅用于匿名块。对于命名的PL/SQL单元来说,这是无效的语法(IS或AS关键字履行了标记变量声明部分的功能)。

所以,你的代码应该这样开始

CREATE OR REPLACE procedure MOBLIE_RX_VERIFICATION 
    (ARG_DAD_ID IN NUMBER, 
    ARG_PATIENT_NAME IN VARCHAR2, 
    ARG_VERIFY_MODE VARCHAR2) 
AS 
    NEW_CCH_ID NUMBER; 
1
  1. 代替 “AS” 到 “IS”
  2. 增“返回号码“或将功能更改为程序
+0

AS和IS是可以互换的 – APC