如何拆分正则表达式时间字符串

Question

在JavaScript中，我有一个时间字符串var time = "12:30:49PM"

我想要小时分离，分，秒，从这个字符串AM/PM。

浏览器stackoverflow我能够找到以下正则表达式，分裂小时，分钟和上午/下午，但我在正则表达式非常糟糕，所以我无法解决如何做秒。

var hours = Number(time.match(/^(\d+)/)[1]); 
var minutes = Number(time.match(/:(\d+)/)[1]); 
var AMPM = time.match(/([AaPp][Mm])$/)[1]; 

如何获得通过正则表达式第二

Answer 1

在你的榜样，你只会做这样的事情：

var time = "12:30:49PM"; 
 
var hours = Number(time.match(/^(\d+)/)[1]); 
 
var minutes = Number(time.match(/:(\d+)/)[1]); 
 
var AMPM = time.match(/([AaPp][Mm])$/)[1]; 
 
var seconds = Number(time.match(/:(\d+):(\d+)/)[2]); 
 
console.log(hours, ":", minutes, ":", seconds, AMPM);

但是，它会更effecient在一个电话让一切：

var time = "12:30:49AM"; 
 
var matches = time.match(/^(\d+):(\d+):(\d+)([AP]M)$/i); 
 
var hours = matches[1]; 
 
var minutes = matches[2]; 
 
var seconds = matches[3]; 
 
var AMPM = matches[4]; 
 
console.log(hours, ":", minutes, ":", seconds, AMPM);

Answer 2

您可以使用正则表达式与ES6阵列解构组合：

const time = "12:30:49PM" 
 
const [hour, min, sec, period] = time.match(/\d+|\w+/g); 
 

 
console.log(hour, min, sec, period);

Answer 3

您可以使用它像这样：

var time = "12:30:49PM" 
 
var hours = Number(time.match(/^(\d+)/)[1]); 
 
var minutes = Number(time.match(/:(\d+)/)[1]); 
 
var sec = Number(time.match(/:(\d+)\D+$/)[1]); 
 
var AMPM = time.match(/([ap]m)$/i)[1]; 
 
console.log(hours); 
 
console.log(minutes); 
 
console.log(sec); 
 
console.log(AMPM);

Answer 4

就劈在结肠和（P \ A）M部分

var time = "12:30:49PM"; 
 
var parts = time.split(/:|(\DM)/).filter(Boolean); 
 

 
console.log(parts)

Answer 5

var sec = Number(time.match(/:([0-9][0-9])/ig)[1].replace(":",""))