我一直在实现sendgrid-ruby gem通过SendGrid发送电子邮件。我正在使用专门用于发送消息的模板。我使用TemplateMailer实现了所有工作。如何将unique_args从Ruby on Rails传递到SendGrid :: TemplateMailer API
这是代码:
unique_args = {unique_args: {MyAuditNumber: "9999999"}}
# Create a sendgid recipient list
recipients = []
recipient = SendGrid::Recipient.new(to_email)
merge_vars.each do |mv|
Rails.logger.debug(mv)
recipient.add_substitution('*|' + mv["name"] + '|*', mv["content"])
end
recipients << recipient
# Create a sendgrid template
template = SendGrid::Template.new(template_id)
# Create a client
client = SendGrid::Client.new(api_key: Rails.configuration.sendgridkey)
mail_defaults = {
from: from_email,
from_name: from_name,
to: to_email,
to_name: to_name,
bcc: bcc,
html: ' ',
text: ' ',
subject: subject
}
mailer = SendGrid::TemplateMailer.new(client, template, recipients)
# send it
lres = mailer.mail(mail_defaults)
我想做的最后一件事是一个唯一的标识符添加到我发送的每条消息。
我读过两个SendGrid文档以及几个问题和其他物品( how to get response of email sent using sendgrid in rails app to save in database http://thepugautomatic.com/2012/08/sendgrid-metadata-and-rails/ https://sendgrid.com/docs/Integrate/Code_Examples/SMTP_API_Header_Examples/ruby.html )
我可以告诉大家,我需要unique_args添加到SMTP API。但是我想不出的是如何将它传递给SendGrid例程。
我已经试过了诸如:
recipient.add_to_smtpapi(unique_args)
和
recipient.add_to_smtpapi(unique_args.to_json)
和
mail_defaults = {
smtpapi: unique_args,
from: from_email,
...
和
mail_defaults = {
smtpapi: unique_args.to_json,
from: from_email,
...
次这些尝试通常导致这样的错误消息: “{\” 未定义的方法`的add_filter” unique_args \ “:{\” MyAuditNumber \ “:\” 9999999 \ “}}”:字符串
没有人知道如何在使用TemplateMailer时传递unique_args?