下划线差异不适用于JSON对象数组

Question

我有一个我想要使用_.difference过滤的用户列表。但它不能用于比较对象。它只适用于我只比较用户名。这里是代码片段：

var users = [ 
     { 
     "username": "user1", 
     "birthdate": "birth1" 
     }, 
     { 
     "username": "user2", 
     "birthdate": "birth2" 
     }, 
     { 
     "username": "user3", 
     "birthdate": "birth3" 
     }, 
     { 
     "username": "user4", 
     "birthdate": "birth4" 
     } 
    ]; 

    var keep = [ 
     { 
     "username": "user1", 
     "birthdate": "birth1" 
     }, 
     { 
     "username": "user3", 
     "birthdate": "birth3" 
     } 
    ]; 

    log(_.difference(_.pluck(users,"username"),_.pluck(keep,"username"))); // works 
    log(_.difference(users,keep)); // this is what I want, does not work 

任何想法？谢谢 - C.

注：这样做是为followss的替代方式，但不知道的效率：

 log(_.filter(users, function(num){ 
     return (!_.contains(_.pluck(keep,"username"),num.username)) 
    })); 

Answer 1

这些对象的数组，其仅视为引用（如地址） 。由于它们不是相同对象实例的引用（即使它们包含相同的信息），它们被认为是完全不同的。

_.difference不会对数组内容进行深入检查，它只是查看值并看到它们是对象引用。

如果你想要的对象

var users = [{ "username": "user1", "birthdate": "birth1" }, { "username": "user2", "birthdate": "birth2" }, { "username": "user3", "birthdate": "birth3" }, { "username": "user4", "birthdate": "birth4" }]; 
 
var keep = [{ "username": "user1", "birthdate": "birth1" }, { "username": "user3", "birthdate": "birth3" }]; 
 

 
// if you want to compare all the properties 
 
var result = _.reject(users, _.partial(_.findWhere, keep, _)); 
 

 
console.log("All attributes", result); 
 

 
// if the username is the identifying field 
 
var keepUsernames = _.pluck(keep, 'username'); 
 
result = _.reject(users, (user) => _.indexOf(keepUsernames, user.username) > -1); 
 

 
console.log("usernames", result);

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