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我正试图在jQuery中使用.clone()。我有一个$ .post retuning一个id号码,我想改变克隆的元素。如果我克隆父母和孩子更改id属性,我该如何使用.data?我还有一个绑定到我想在克隆后保留的select标签的更新。克隆并保留绑定的事件和更改克隆元素中的属性
HTML:
<div id="basicinfobox">
<table id="ethnicitytable">
<tbody>
<tr valign="top">
<td>
<img id="Ethnicity" ref="6" rel="ActorEthnicity" src="plussm.png">
</td>
<td id="ethnicity22">
<select id="22" rel="ActorEthnicity" name="Ethnicity">
<option value="">Ethnicity</option>
<option value="Caribbean">Caribbean</option>
</select>
<img id="22" border="0" width="16" height="16" onclick="ethnicitydelete(this.id)" alt="Delete Ethnicity" src="deletessm.png">
</td>
</tr>
</tbody>
</table>
</div>
的Jquery:
$('#basicinfobox img[src*="plus"]').click(function(){
var rel=$(this).attr('rel');
alert(rel)
var ref=$(this).attr('ref');
alert(ref);
//$('#ethnicitytable tr td:last').clone().appendTo('#ethnicitytable tr:last');
$.post('add.php', {rel: rel}, function(id){
var elem = $('#ethnicitytable tr td:last')[0];
clone = elem.clone(true);
jQuery.data(clone, "id", id);
clone.appendTo('#ethnicitytable tr:last');
//$('#ethnicitytable td:last').attr('id', 'ethnicity'+id);
//$('#ethnicitytable select:last').attr('id', id);
//$('#ethnicitytable img[src="deletessm.png"]:last').attr('id', id);
})
})