检查表中的字段是否有空格或逗号 - MS-Access

Question

我有一个名为FinalForgotten的表，它只包含一个名为aname的字段。该领域可能看起来像史密斯约翰或史密斯约翰。所以最后和名字都在同一个字段中，并由空格或逗号分隔。防御字段包含三个字段：first_name，last_name，middle_initial。 first_name字段将包含完全匹配数据IN aname字段（例如John）的数据。 last_name字段将包含与aname字段中的一段数据完全匹配的数据（例如Smith）。我试图把所有的FinalForgotten aname记录与一个中间的首字母变成一张新表（例如Smith，John S）。防守表是这个中间名首字母。

这会工作：

SELECT left([aname],InStr(1,[aname],",")-1) & " "& right([aname],Len(aname)-InStr(1,[aname],",")) & " "& summary_judgment.middle_initial AS fullnameINTO FinalForgottenWithMiddle FROM FinalForgotten INNER JOIN summary_judgment ON((left(FinalForgotten.aname,InStr(1,FinalForgotten.[aname],",")-1))=summary_judgment.last_name) AND((right(FinalForgotten.aname,Len(FinalForgotten.aname)-InStr(1,FinalForgotten.[aname],","))=summary_judgment.first_name)); 

但它会返回“无效过程调用”应该FinalForgotten包含不具有像一个逗号的字段： 史密斯约翰。

因此，要解决这个问题，我试图因素逗号是否是在外地或不：

SELECT left([aname], IIF(instr([aname], ",") = 0, InStr(1,[aname]," ")-1),InStr(1,[aname],",")-1) & ", " & right([aname], IIF(instr([aname], ",") = 0,Len(aname)-InStr(1,[aname]," "),Len(aname)-InStr(1,[aname],",") & " " & defense_final.middle_initial AS fullname INTO FinalForgottenWithMiddle 
FROM FinalForgotten INNER JOIN defense_final ON 
((right(FinalForgotten.aname,IIF(instr([aname], ",") = 0,Len(FinalForgotten.aname)-InStr(1,FinalForgotten.[aname]," ")),Len(FinalForgotten.aname)-InStr(1,FinalForgotten.[aname],","))=defense_final.first_name)) 
AND 
((left(FinalForgotten.aname,,IIF(instr([aname], ",") = 0,InStr(1,FinalForgotten.[aname]," ")-1)),InStr(1,FinalForgotten.[aname],",")-1))=defense_final.last_name); 

这给了我一个“缺少运算符语法”错误，并强调作为字。

感谢您的回复。

Answer 1

似乎有不少遗漏的括号。

SELECT left(
     [aname], 
     IIF(instr([aname], ",") = 0, 
     InStr(1,[aname]," ")-1, 
     InStr(1,[aname],",")-1 
     ) 
    ) 
    & ", " & 
    right(
     [aname], 
     IIF(instr([aname], ",") = 0, 
     Len(aname)-InStr(1,[aname]," "), 
     Len(aname)-InStr(1,[aname],",") 
     ) 
     ) 
    & " " & 
    defense_final.middle_initial AS fullname 
INTO FinalForgottenWithMiddle 
FROM FinalForgotten 
INNER JOIN defense_final 
ON 

    right(FinalForgotten.aname, 
    IIF(instr([aname], ",") = 0, 
    Len(FinalForgotten.aname)-InStr(1,FinalForgotten.[aname]," "), 
    Len(FinalForgotten.aname)-InStr(1,FinalForgotten.[aname],",") 
    ) 
    )=defense_final.first_name 

AND 

    left(FinalForgotten.aname, 
    IIF(instr([aname], ",") = 0, 
     InStr(1,FinalForgotten.[aname]," ")-1, 
     InStr(1,FinalForgotten.[aname],",")-1 
     ) 
    )=defense_final.last_name