整型到char数组转换C

Question

我有下面的代码。我想通过将值增加1（）来修改packet_received的前三个字符（001）。但是，我得到下面的输出，当我运行代码：

Hop_network = 001 
new Hop_network = 2 
packet_received = 2 

我想看到的是：

packet_received = 002456

我该怎么办呢？当第一个字符不是0时，代码工作正常，并且receid消息始终不必始终为0。谢谢你的答案。

int main(int argc,char *argv[]){ 
    char Hop_network[4]; 
    char packet_received[]= "001456"; 
    int Hop_increaser; 

    Hop_network[0] = packet_received[0]; 
    Hop_network[1] = packet_received[1]; 
    Hop_network[2] = packet_received[2]; 
    Hop_network[3] = '\0'; 
    printf("Hop_network = %s\n", Hop_network); 

    Hop_increaser = atoi(Hop_network); 
    Hop_increaser = Hop_increaser + 1; 
    sprintf(Hop_network, "%d", Hop_increaser); 
    printf("new Hop_network = %s\n", Hop_network); 

    packet_received[0] = Hop_network[0]; 
    packet_received[1] = Hop_network[1]; 
    packet_received[2] = Hop_network[2]; 
    printf("packet_received = %s\n", packet_received); 
    return 0; 
} 

Answer 1

您可以使用宽度说明符sprintf来左对齐数字。

sprintf(Hop_network, "%03d", Hop_increaser); 

这意味着“左对齐零到宽度3”。

所有格式说明符的文档可以在这里找到：http://www.cplusplus.com/reference/clibrary/cstdio/sprintf/