如何通过使用xdocument从xml文件中获取值

Question

我有一个xmfile文件，如下所示，我必须获取所有节点值CIName,Type,Status,FriendlyName,AccountNo。我试图通过使用XDocument而没有成功。

<?xml version="1.0" encoding="utf-8"?> 
<RetrievedeviceListResponse xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" schemaRevisionLevel="0" returnCode="0" status="SUCCESS" message="Success" schemaRevisionDate="2015-03-24"> 
    <instance uniquequery="file.device,logical.name=&quot;mss-abb-aejaljabelalifz-ra&quot;" query="" xmlns="http://schemas.hp.com/SM/7"> 
    <file.device type="Structure"> 
     <CIName type="String">mss-abb-aejaljabelalifz-ra</CIName> 
     <Type type="String">networkcomponents</Type> 
     <Status type="String">In use</Status> 
     <FriendlyName type="String">Jabel Ali Free Zone</FriendlyName> 
     <Company type="String">ABB - MWAN</Company> 
    </file.device> 
    <file.networkcomponents type="Structure"> 
     <AccountNo type="String">1444016683</AccountNo> 
    </file.networkcomponents> 
    <attachments xsi:nil="true" /> 
    </instance> 
    <instance uniquequery="file.device,logical.name=&quot;mss-abb-aldar-ra&quot;" query="" xmlns="http://schemas.hp.com/SM/7"> 
    <file.device type="Structure"> 
     <CIName type="String">mss-abb-aldar-ra</CIName> 
     <Type type="String">networkcomponents</Type> 
     <Status type="String">In use</Status> 
     <FriendlyName type="String">Al Dar AUH Main</FriendlyName> 
     <Company type="String">ABB - MWAN</Company> 
    </file.device> 
    <file.networkcomponents type="Structure"> 
     <AccountNo type="String">1222229614</AccountNo> 
    </file.networkcomponents> 
    <attachments xsi:nil="true" /> 
    </instance> 
<instance uniquequery="file.device,logical.name=&quot;mss-abb-aldar-rb&quot;" query="" xmlns="http://schemas.hp.com/SM/7"> 
    <file.device type="Structure"> 
     <CIName type="String">mss-abb-aldar-rb</CIName> 
     <Type type="String">networkcomponents</Type> 
     <Status type="String">In use</Status> 
     <FriendlyName type="String">Al Dar-AUH-Backup</FriendlyName> 
     <Company type="String">ABB - MWAN</Company> 
    </file.device> 
    <file.networkcomponents type="Structure"> 
     <AccountNo type="String">1222222368</AccountNo> 
    </file.networkcomponents> 
    <attachments xsi:nil="true" /> 
    </instance> 
</RetrievedeviceListResponse> 

我用下面的代码

XDocument xdoc = XDocument.Load(path); 
var authors = xdoc.Descendants("RetrievedeviceListResponse"); 

foreach (var author in authors) 
{ 
    Console.WriteLine("{0}{1}",author.Name, author.Value); 
} 

Answer 1

如何像：

var doc = XDocument.Load(@"C:\TestCases\test.xml"); 
     foreach (var node in doc.Descendants().Where(x => "CIName Type Status FriendlyName AccountNo".Contains(x.Name.LocalName))) 
     { 
      Console.WriteLine(string.Format("{0}:{1}", node.Name.LocalName, node.Value)); 
     } 

或纯LINQ：

XDocument.Load(@"C:\TestCases\test.xml").Descendants().Where(x => "CIName Type Status FriendlyName AccountNo".Contains(x.Name.LocalName)).ToList().ForEach(x => Console.WriteLine(string.Format("{0}:{1}", x.Name.LocalName, x.Value))); 

你不关闭你的 “RetrievedeviceListResponse” 在XML太。

Answer 2

XmlDocument doc = new XmlDocument(); 
doc.Load(path); // Where path is the location of the XML file 

XmlNodeList nodes = doc.DocumentElement.SelectNodes("RetrieveDeviceListResponse"); 

for (int i = 0; i < nodes.Count; i++) 
{ 
    Console.WriteLine("Parent Node - {0}", nodes[i].InnerText); 
    for(int j = 0; j < nodes[i].ChildNodes.Count; j++) 
    { 
     Console.WriteLine("Child Node - {0}", nodes[i].ChildNodes[j].InnerText); 
    } 
} 

这是不是你在找什么？

Answer 3

因此，也许你可以使用这样的事情：

  const string @namespaceName = "http://schemas.hp.com/SM/7"; 
      XDocument xdoc = XDocument.Load(path); 
      var authors = xdoc.Descendants(XName.Get("instance", @namespaceName)); 

      foreach (var author in authors) 
      { 
       string ciName = author.Descendants(XName.Get("CIName", namespaceName)).First().Value; 
       string type = author.Descendants(XName.Get("Type", namespaceName)).First().Value; 
       string frendlyName = author.Descendants(XName.Get("Type", namespaceName)).First().Value; 
       string accountNo = author.Descendants(XName.Get("AccountNo", namespaceName)).First().Value; 
       Console.WriteLine("{0}, {1}, {2}, {3}", ciName, type, frendlyName, accountNo); 
      } 

您必须使用此命名空间，如果你想使用此代码：

using System.Linq; 
using System.Xml.Linq;