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我试图写一个日历。但for循环只会打印出第一个月的日子。如果我尝试打印循环后的日子,它将工作。有谁知道发生了什么事?Python:For循环没有按预期迭代
cal_year = input('Enter a year (YYYY): ')
def not_common(year):
if (year % 4 == 0):
if (year % 100 == 0):
if (year % 400 == 0):
return 1
else:
return 0
else:
return 1
else:
return 0
leap = not_common(cal_year)
if leap == 0:
print 'This is not a leap year'
elif leap == 1:
print 'This is a leap year'
else:
print 'unexpected calculation error'
y1900=1
day = ((cal_year-1900)*365)%7
month = ['Jan','Feb','Mar','Apr','May','Jun','Jul','Aug','Sep','Oct','Nov','Dec']
calendar = [range(1,32), range(1,29), range(1,32), range(1,31), range(1,32), range(1,31),\
range(1,32),range(1,32),range(1,31),range(1,32),range(1,31),range(1,32)]
if (leap == 1):
calendar[1] = range(1,30)
week = ['su','mo','tu','we','th','fr','sa']
r = 0
for i in range(0,12):
print month[i]
print ' '.join(str(y) for y in week)
for j in range (1, (len(calendar[i])/7)+2):
#cal =' '.join(str(x).zfill(2) for x in calendar[i][r*7:7*(r+1)])
print ' '.join(str(x).zfill(2) for x in calendar[i][r*7:7*(r+1)])
r += 1
print
print calendar[1]
print calendar[11]
麻烦的线被认为是: '。加入(STR(x)的.zfill(2)在日历X [I] [R * 7:7 *(R + 1)] )
@马克的答案指出了这个程序的一些问题。另一个问题是你计算'日',假定在给定年份和1900年之间没有闰年。这实际上并没有影响代码,因为它不会使用'日'。 –