在验证数据库中值的心不是已经

我试图验证输入的电子邮件地址是不是已经在我的数据基础。我有以下代码：在验证数据库中值的心不是已经

继承人在我的HTML我的形式

<form action="signup.php" method="post" onsubmit="return validateForm(this);"> 
       <input type="text" name="First_name" placeholder="First Name" required pattern="[A-Za-z].{2,}" maxlength="20" oninvalid="this.setCustomValidity('Must be between 2 and 20 characters long and no numbers!')"/> 
       <input type="text" name="Last_name" placeholder="Last Name" required pattern="[A-Za-z']..{2,}" maxlength="20" oninvalid="this.setCustomValidity('Must be between 2 and 20 characters long! and no numbers')"/> 
       <input type="email" pattern="[a-z0-9._%+-][email protected][a-z0-9.-]+\.[a-z]{2,4}$" name="Email" required placeholder="Email Address" maxlength="30" oninvalid="this.setCustomValidity('Must be a validate Email Address!')"/> 
       <input type="email" pattern="[a-z0-9._%+-][email protected][a-z0-9.-]+\.[a-z]{2,4}$" name="Email2" required placeholder="Comfirm Email Address" maxlength="30" oninvalid="this.setCustomValidity('Must be a validate Email Address!')"/> 
       <input type="password" name="Password" placeholder="Password" required maxlength="20" required pattern=".{6,}" oninvalid="this.setCustomValidity('Must be between 6 and 20 characters long!')"/> 
       <input type="Submit" value="Submit" name="Submit" id="Submit"/> 
       </form>

我的继承人在HTML顶部的jQuery：

<script type="text/javascript" src="js/jquery.js"></script> 
<script type="text/javascript"> 
$(document).ready(function() { 
    //result texts 
    var email_error = 'Emails do not match!'; 
    alert("Hi"); 
    //when button is clicked 
    $('#Submit').click(function(){ 
    //run the character number check 
    if($('#Email').val() != $('#Email2').val()){ 
     //if it's bellow the minimum show characters_error text ' 
     $('#emailValidate').html(email_error); 
    }else{ 
     //else show the cheking_text and run the function to check 
     check_availability(); 
    } 
    }); 

}); 

//function to check username availability 
function check_availability(){ 

    //get the username 
    var Email = $('#Email').val(); 

    //use ajax to run the check 
    $.post("checkmail.php", { Email: Email }, 
     function(result){ 
     //if the result is 1 
     if(result == 1){ 
      //show that the username is available 
      $('#emailValidate').html(Email + ' is Available'); 
     }else{ 
      //show that the username is NOT available 
      $('#emailValidate').html(Email + ' is not Available'); 
     } 
    }); 

} 
</script>

这是我的PHP文件

<?php 
$servername = "localhost"; 
$username = "root"; 
$password = "root"; 
$DB = "database"; 

// Create connection 
$conn = mysqli_connect($servername, $username, $password, $DB); 

// Check connection 
if ($conn->connect_error) { 
    die("Connection failed: " . $conn->connect_error); 
} 

$sql = "SELECT Email FROM Users WHERE Email = '".$_POST['Email']."'"; 
$select = mysqli_query($conn, $sql); 
$row = mysqli_num_rows($select); 

if($row > 0)) { 
    echo 1; 
}else 
echo 0; 
?>

现在，当我点击提交没有发生逻辑。由于某种原因，它没有检测到提交和不评估。我使用提交作为ID，它不是拿起它。我错误地处理了这个问题吗？

来源

2015-07-19 user081608

我没有看到'validateForm（）'函数。你也没有身份证。 –

由于'Email'是一个文本字段，你必须使用像引号：'WHERE电子邮件=“;'，注意到你的代码也vurnable SQL注入 – Cyclonecode

$。员额“” [电子邮件‘$ _ POST’。”“ （“checkmail.php”？{电子邮件：电子邮件}，哪里是电子邮件 – jrath

你可以把它使得SQL数据库列必须是潮头。因此，SQL会为你做，并且你可以提交你的表单。如果存在与提交的电子邮件相匹配的电子邮件，则SQL将发出约束错误。

来源

2015-07-19 20:05:58 noahdotgansallo

我已经有了，但我想允许用户在现场更改他们的电子邮件地址。这种方法可能吗？ – user081608

@ user081608我会通过JavaScript/jQuery提交表单，这样如果出现错误，您可以提醒用户并允许他们更改电子邮件。 – noahdotgansallo

在验证数据库中值的心不是已经

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