PHP每个或每个打印数据

Question

首先感谢您的关注！

运行查询后，我有这样的结果：

-------------------------------------- 
|post_id| meta_key | meta_value | 
-------------------------------------- 
| 1 |  name  | jeff  | 
-------------------------------------- 
| 1 |  email | x@mail.com | 
-------------------------------------- 
| 1 |  color |  blue | 
-------------------------------------- 
| 2 |  name  | mary  | 
-------------------------------------- 
| 2 |  email | y@mail.com | 
-------------------------------------- 
| 2 |  color |  pink | 
-------------------------------------- 

的阵列

array(6) 
{ 
    [0]=> object(stdClass)#448 (3) 
     { 
      ["post_id"]  => string(1) "1" 
      ["meta_key"] => string(4) "name" 
      ["meta_value"] => string(4) "jeff" 
     } 
    [1]=> object(stdClass)#449 (3) 
     { 
      ["post_id"]  => string(1) "1" 
      ["meta_key"] => string(4) "email" 
      ["meta_value"] => string(10) "x@mail.com" 
     } 
    [2]=> object(stdClass)#450 (3) 
     { 
      ["post_id"]  => string(1) "1" 
      ["meta_key"] => string(5) "color" 
      ["meta_value"] => string(4) "blue" 
     } 
    [3]=> object(stdClass)#448 (3) 
     { 
      ["post_id"]  => string(1) "2" 
      ["meta_key"] => string(4) "name" 
      ["meta_value"] => string(4) "mary" 
     } 
    [4]=> object(stdClass)#449 (3) 
     { 
      ["post_id"]  => string(1) "2" 
      ["meta_key"] => string(4) "email" 
      ["meta_value"] => string(10) "y@mail.com" 
     } 
    [5]=> object(stdClass)#450 (3) 
     { 
      ["post_id"]  => string(1) "2" 
      ["meta_key"] => string(5) "color" 
      ["meta_value"] => string(4) "pink" 
     } 

}

好，我有3个标签和3个值1组的ID。使用PHP，我需要知道如何做一个foreach或每个打印这个数据是这样的：现在

--------------------------------------------------- 
|post_id| name  | email | color | 
--------------------------------------------------- 
| 1 | jeff  | x@mail.com | blue  | 
--------------------------------------------------- 
| 2 | mary  | y@mail.com | pink  | 
--------------------------------------------------- 

，与科斯塔斯Mitsarakis的帮助下，我有一个代码，但是这个代码，于我而言，是返回NULL值。

代码：

global $wpdb; 

$meta_value = interested_get_meta('interested_email'); 
$results = $wpdb->get_results( 
     'SELECT post_id, meta_key, meta_value 
     FROM wp_postmeta 
     WHERE post_id 
     IN ( SELECT post_id 
       FROM wp_postmeta 
       WHERE meta_value = "'.$meta_value.'" 
      )', OBJECT 
); 

$data = array(); 
$result = array($results); 

foreach($result as $key => $value) { 
    if (!in_array($value['post_id'], $data)) { 
     $data[$value['post_id']]['post_id'] = $value['post_id']; 
    } 
    if ($value['meta_key'] != 'post_id') { 
     $data[$value['post_id']][$value['meta_key']] =  $value['meta_value']; 
    } 
} 

var_dump($data); 

的var_dump的回报：

array(1) { [""]=> array(2) { ["post_id"]=> NULL [""]=> NULL } } 

Answer 1

我在上面说的意见@KostasMitsarakis同意这可能是更好的SQL级别上完成的。

不过这里是你可能寻找的PHP代码：

<?php 

$input = [ 
    [ 
     'id' => 1, 
     'name' => 'jeff', 
     'email' => 'x@mail.com', 
     'color' => 'blue', 
    ], 
    [ 
     'id' => 2, 
     'name' => 'mary', 
     'email' => 'y@mail.c', 
     'color' => 'pink', 
    ] 
]; 

$output = []; 
foreach ($input as $entry) { 
    $element = []; 
    foreach($entry as $key=>$val) { 
     $element[$key] = $val; 
    } 
    $output[] = $element; 
} 


var_dump($output); 

这样做的输出继电器是：

array(2) { 
    [0] => 
    array(4) { 
    'id' => 
    int(1) 
    'name' => 
    string(4) "jeff" 
    'email' => 
    string(10) "x@mail.com" 
    'color' => 
    string(4) "blue" 
    } 
    [1] => 
    array(4) { 
    'id' => 
    int(2) 
    'name' => 
    string(4) "mary" 
    'email' => 
    string(8) "y@mail.c" 
    'color' => 
    string(4) "pink" 
    } 
} 

Answer 2

你可以用一个简单的foreach改变你的阵列：

$output = array(); 
foreach ($input as $data) { 
    $output[$data['id']]['id'] = $data['id']; 
    $output[$data['id']][$data['label']] = $data['value']; 
} 

Answer 3

尝试使用ARRAY_A作为数组获得结果。

$meta_value = interested_get_meta('interested_email'); 
$results = $wpdb->get_results( 
     'SELECT post_id, meta_key, meta_value 
     FROM wp_postmeta 
     WHERE post_id 
     IN ( SELECT post_id 
       FROM wp_postmeta 
       WHERE meta_value = "'.$meta_value.'" 
      )', ARRAY_A 
); 

$data = array(); 
$result = json_decode($results , true); //Return results as array 

foreach($result as $key => $value) { 
    if (!in_array($value['post_id'], $data)) { 
     $data[$value['post_id']]['post_id'] = $value['post_id']; 
    } 
    if ($value['meta_key'] != 'post_id') { 
     $data[$value['post_id']][$value['meta_key']] = $value['meta_value']; 
    } 
} 
echo 'id name email color <br />'; 
foreach($data as $key => $value) { 
    echo $value['post_id'].' '.$value['name'].' '.$value['email'].' '.$value['color'].'<br />'; 
} 

var_dump($data); 

结果（表）

id name email color 
1 jeff x@mail.com blue 
2 mary y@mail.com pink 

结果（的var_dump）

array (size=2) 
    1 => 
    array (size=4) 
     'post_id' => int 1 
     'name' => string 'jeff' (length=4) 
     'email' => string 'x@mail.com' (length=10) 
     'color' => string 'blue' (length=4) 
    2 => 
    array (size=4) 
     'post_id' => int 2 
     'name' => string 'mary' (length=4) 
     'email' => string 'y@mail.com' (length=10) 
     'color' => string 'pink' (length=4) 

Answer 4

好，几个小时和咖啡后，与所有的人的帮助，已经写了在这里，我找到了解决方案。

$meta_value = interested_get_meta('interested_email'); 

    global $wpdb; 
    $results = $wpdb->get_results( 
      'SELECT post_id, meta_key, meta_value 
      FROM wp_postmeta 
      WHERE post_id 
      IN ( SELECT post_id 
        FROM wp_postmeta 
        WHERE meta_value = "'.$meta_value.'" 
       )', OBJECT 
    ); 

    $data = array(); 

    if (is_array($results)) { 
     foreach($results as $item) { 
      $data[$item->post_id]['post_id']   = $item->post_id; 
      $data[$item->post_id][$item->meta_key] = $item->meta_value; 
     } 
    } 

    foreach ($data as $key => $value) { ?> 
     <li> 
      <?php echo $value['post_id'];?><br/> 
      <?php echo $value['name'];?><br/> 
      <?php echo $value['color'];?><br/> 
     </li> 
    <?php } 

感谢大家谁以任何方式帮助！