在MySQL中创建交叉表查询

Question

我有一个MySQL表，可以在一天中的不同时间点和不同位置跟踪某些总计。我试图创建一个查询，不仅将每个列，而且每个行。我到目前为止的查询总计每列，但我无法弄清楚如何获得每行的总数。

这是我的查询：

SELECT * FROM 
(SELECT IFNULL(hour,"Total") as hour, SUM(location1), SUM(location2), SUM(location3), SUM(location4), SUM(location), FROM counts WHERE ay = 'AY1617' GROUP BY hour WITH ROLLUP) as crossdata 
ORDER BY FIELD (hour,'8:00am','9:00am','10:00am','11:00am','12:00pm','1:00pm','2:00pm','3:00pm','4:00pm','5:00pm','6:00pm','7:00pm','8:00pm','9:00pm','10:00pm','11:00pm') 

这是最终我想输出的样子：

hour location1 location2 location3 location4 totals 
8am  4    3   2   1   10 
9am  1    2   2   1   6 
10am  2    3   2   3   10 
totals  7    8   6   5   26 

我怎样才能做到这一点？

Answer 1

值得一提的是，这不是交叉表查询。你没有将行转换为列。

我尝试此查询并得到结果，你想：

SELECT IFNULL(hour, 'Total') AS hour, 
    SUM(location1) AS location1, 
    SUM(location2) AS location2, 
    SUM(location3) AS location3, 
    SUM(location4) AS location4, 
    SUM(location1)+SUM(location2)+SUM(location3)+SUM(location4) AS totals 
FROM counts 
WHERE ay = 'AY1617' 
GROUP BY hour WITH ROLLUP; 

你真的应该使用TIME数据类型，而不是为小时字符串。然后它只是正确排序。

+----------+-----------+-----------+-----------+-----------+--------+ 
| hourt | location1 | location2 | location3 | location4 | totals | 
+----------+-----------+-----------+-----------+-----------+--------+ 
| 08:00:00 |   4 |   3 |   2 |   1 |  10 | 
| 09:00:00 |   1 |   2 |   2 |   1 |  6 | 
| 10:00:00 |   2 |   3 |   2 |   3 |  10 | 
| Total |   7 |   8 |   6 |   5 |  26 | 
+----------+-----------+-----------+-----------+-----------+--------+