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这是我在Arduino板上编程的第一年。出于某种原因,我的串口监视器不会接受任何用户输入,我做错了什么?我需要两个用户输入作为浮点变量,然后在我设置的自定义函数中使用。串行监视器不接受用户输入arduino c编程
float contSurfArea(float x, float y){
float z;
z = (3.14159*x*x)+(2*3.14159*x*y);
return (z);
}
void setup()
{
Serial.begin(9600); //serial communication initialized
}
void loop(){
float baseRad, contHeight;
Serial.println("Open-top Cylindrical Container Program");
delay(2000);
Serial.println("Radius of the base(in meters): ");
while(Serial.available()<=0)
baseRad= Serial.parseFloat();
delay(2000);
Serial.println("Height of the container(in meters): ");
while(Serial.available()<=0)
contHeight= Serial.parseFloat();
delay(2000);
float q;
q = contSurfArea(baseRad, contHeight);
Serial.print("The surface area of your container is: ");
Serial.print(q);
Serial.print("meters^2");
}
Pleasefixyourindentatiionelseyourcodeistoodifficulttoread – 2014-10-19 22:46:54