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我试图让一个登录形式,但我无法弄清楚如何从组合框我这样做,用户名:登录表单组合框实体框架错误
XAML:
<StackPanel>
<Grid Height="274">
<Label Content="LOGGARSI PER ENTRARE" HorizontalContentAlignment="Center" FontWeight="Bold" FontSize="24" FontFamily="Sitka Heading" Margin="0,0,0,230" />
<Label Content="Username" HorizontalAlignment="Left" Margin="68,64,0,0" VerticalAlignment="Top" Style="{StaticResource LabelStyle}"/>
<ComboBox x:Name="ComboUsers" ItemsSource="{Binding}" DisplayMemberPath="userName" SelectedValuePath="userName" SelectedItem="{Binding Path=userName}" HorizontalAlignment="Left" Margin="209,72,0,0" VerticalAlignment="Top" Width="120"/>
<Label Content="Password" HorizontalAlignment="Left" Margin="68,114,0,0" VerticalAlignment="Top" Style="{StaticResource ResourceKey=LabelStyle}"/>
<PasswordBox x:Name="passBox" HorizontalAlignment="Left" Margin="209,114,0,0" VerticalAlignment="Top" Width="120" Height="30"/>
<Button x:Name="BtnLogIn" Content="Entra" HorizontalAlignment="Left" Margin="158,204,0,0" VerticalAlignment="Top" Width="76" Click="BtnLogIn_Click"/>
</Grid>
</StackPanel>
这为代码在:
NioRepairContext ctx;
public MainWindow()
{
InitializeComponent();
FillComboUsers();
}
public List<User> user { get; set; }
private void FillComboUsers()
{
ctx = new NioRepairContext();
var item = ctx.Users.ToList();
user = item;
DataContext = user;
}
private void BtnLogIn_Click(object sender, RoutedEventArgs e)
{
var user = ctx.Users.Where(i => i.userName == ComboUsers.SelectedItem.ToString()).FirstOrDefault();
if (user == null)
{
MessageBox.Show("Login Fallito, Credenziali inesatte");
}
if (user.userName == ComboUsers.SelectedItem.ToString() && user.password == passBox.Password.ToString())
{
MessageBox.Show("Benvenuto " + user.userName+ ", Login Corretto");
}
else
{
MessageBox.Show("Login Fallito, Credenziali inesatte");
}
}
如果我砍死的组合框结合或其他
坦克的回答帮我解决 – Nio74
请记住接受的答案,那么:https://meta.stackexchange.com/questions/23138/how-to-accept-the -answer-上堆栈上溢 – mm8