Django的 - 类型错误：“类型”是这个函数

我使用Django和我在运行使用Django模型Django的 - 类型错误：“类型”是这个函数

，我使用该脚本需要一个Python脚本问题无效的关键字参数从一个API，并将其加载到我的数据库的数据，但是，我得到一个类型错误，而试图运行它：

>>> exec(open('load_from_api.py').read()) 
Traceback (most recent call last): 
    File "C:\Program Files (x86)\Python35-32\lib\site-packages\django\core\managem 
ent\commands\shell.py", line 69, in handle 
    self.run_shell(shell=options['interface']) 
    File "C:\Program Files (x86)\Python35-32\lib\site-packages\django\core\managem 
ent\commands\shell.py", line 61, in run_shell 
    raise ImportError 
ImportError 

During handling of the above exception, another exception occurred: 

Traceback (most recent call last): 
    File "C:\Program Files (x86)\Python35-32\lib\site-packages\django\db\models\qu 
ery.py", line 465, in get_or_create 
    return self.get(**lookup), False 
    File "C:\Program Files (x86)\Python35-32\lib\site-packages\django\db\models\qu 
ery.py", line 387, in get 
    self.model._meta.object_name 
movies.models.DoesNotExist: Movie matching query does not exist. 

During handling of the above exception, another exception occurred: 

Traceback (most recent call last): 
    File "<console>", line 1, in <module> 
    File "<string>", line 24, in <module> 
    File "C:\Program Files (x86)\Python35-32\lib\site-packages\django\db\models\ma 
nager.py", line 122, in manager_method 
    return getattr(self.get_queryset(), name)(*args, **kwargs) 
    File "C:\Program Files (x86)\Python35-32\lib\site-packages\django\db\models\qu 
ery.py", line 467, in get_or_create 
    return self._create_object_from_params(lookup, params) 
    File "C:\Program Files (x86)\Python35-32\lib\site-packages\django\db\models\qu 
ery.py", line 499, in _create_object_from_params 
    obj = self.create(**params) 
    File "C:\Program Files (x86)\Python35-32\lib\site-packages\django\db\models\qu 
ery.py", line 399, in create 
    obj = self.model(**kwargs) 
    File "C:\Program Files (x86)\Python35-32\lib\site-packages\django\db\models\ba 
se.py", line 443, in __init__ 
    raise TypeError("'%s' is an invalid keyword argument for this function" % li 
st(kwargs)[0]) 
TypeError: 'genre' is an invalid keyword argument for this function

电影模式：

class Movie(models.Model): 
    title = models.CharField(max_length=511) 
    tmdb_id = models.IntegerField(null=True, blank=True) 
    release = models.DateField(null=True, blank=True) 
    poster = models.TextField(max_length=500) 
    backdrop = models.TextField(max_length=500, null=True, blank=True) 
    rating = models.FloatField(null=True, blank=True) 
    description = models.TextField() 
    director = models.ManyToManyField(Person, related_name="directed_movies") 
    actors = models.ManyToManyField(Person, related_name="acted_movies") 
    genre = models.ManyToManyField(Genre)

和我使用从脚本片段：

for movie in results: 
    data = Movie.objects.get_or_create(title=movie['title'], 
             tmdb_id=movie['id'], 
             release=movie['release_date'], 
             genre=movie['genre_ids'], 
             description=movie['overview'], 
             backdrop=movie['backdrop_path'], 
             poster=movie['poster_path'])

电影[ 'genre_ids']来以列表的形式：例如[42，67，80]或[12，109]。

我不确定我在哪里错了，任何帮助将不胜感激！

编辑：

当我改变了我的脚本是：

for movie in results: 
    data = Movie.objects.get_or_create(title=movie['title'], 
             tmdb_id=movie['id'], 
             release=movie['release_date'], 
             description=movie['overview'], 
             backdrop=movie['backdrop_path'], 
             poster=movie['poster_path']) 
    genres = [] 
    genres = movie['genre_ids'] 
    for gnre in genres: 
     data.genre.add(gnre)

它给了我下面的错误：

AttributeError: 'tuple' object has no attribute 'genre'

来源

2016-09-16 mari

看起来你需要做'makemigrations'和'migrate' –

在应用程序检测到没有任何变化！ – mari

请参阅[此问题]（http://stackoverflow.com/questions/12254033/django-get-or-create-return-error-tuple-object-has-no-attribute/12254139#12254139）来解释属性错误。 – Alasdair

get_or_create()

Returns a tuple of (object, created), where object is the retrieved or created object and created is a boolean specifying whether a new object was created.

所以不是：

data = Movie.objects.get_or_create(title=movie['title'], 
            ....)

它应该是：

data, created = Movie.objects.get_or_create(title=movie['title'], 
              ....)

来源

2016-09-16 22:59:33 mari

试试这个：

for movie in results: 
    obj, data = Movie.objects.get_or_create(title=movie['title'], 
             tmdb_id=movie['id'], 
             release=movie['release_date'], 
             description=movie['overview'], 
             backdrop=movie['backdrop_path'], 
             poster=movie['poster_path']) 
    genre_ids = movie['genre_ids'] 
    genres = Genre.objects.filter(id__in=genre_ids) 
    obj.genre.add(*genres)

来源

2016-09-16 22:56:22 arcegk

恐怕没有工作，它给了我一个NameError：name'Genre'not defined – mari

您应该导入Genre模型，'from yourapp.models import Genre' – arcegk

它给了我AttributeError：'bool'object has no属性'类型' – mari

Django的 - 类型错误：“类型”是这个函数

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