我有一些问题。Jpa多对多如何将数据插入到两个表中
我有3个表:
users (id, name, ..)
roles (id, name)
user-role (user_id, role_id)
当我做很多一对多的关系,确实省了()我有3个刀片。
用户:
@Entity
@Table(name = "user")
public class User implements Serializable {
public static final String UK_EMAIL = "uk_email";
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "id")
private Long id;
@ManyToMany(fetch = FetchType.LAZY, cascade = {CascadeType.PERSIST, CascadeType.MERGE})
@JoinTable(
name = "system_user_role",
joinColumns = {@JoinColumn(name = "user_id", referencedColumnName = "id")},
inverseJoinColumns = {@JoinColumn(name = "role_id", referencedColumnName = id")}
)
private List<SystemRole> userRole;
public List<SystemRole> getUserRole() {
return userRole;
}
SystemRole;
@Entity
@Table(name = "system_role")
public class SystemRole implements Serializable {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "id")
private Long id;
@Column
private String name;
@ManyToMany(fetch = FetchType.LAZY)
@JoinTable(
name = "system_user_role",
joinColumns = {@JoinColumn(name = "role_id", referencedColumnName = "id")},
inverseJoinColumns = {@JoinColumn(name = "user_id", referencedColumnName = "id")}
)
private List<User> users;
public List<User> getUsers() {
return users;
}
public void setUsers(List<User> users) {
this.users = users;
}
public Long getId() {
return id;
}
public void setId(Long id) {
this.id = id;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
}
请告诉我,我可以将数据插入到两个表只,只进(用户和USER_ROLE? 我的角色名单,我不必添加一个新的角色,当我创建一个新的用户。
所以,当我这样做:
SystemRole role1 = systemRoleService.findOne("ROLE_ADMIN");
userForm.setUserRole(Lists.newArrayList(role1));
....
final User saved = userRepository.save(user);
....
我得到一个错误:
org.springframework.dao.InvalidDataAccessApiUsageException: detached entity passed to persist:...
如果我这样做:
@Service("userService")
@Transactional
public class UserServiceImpl implements UserDetailsService, ResourceService<User> {
private final static Logger LOGGER = LoggerFactory.getLogger(UserServiceImpl.class);
@Autowired
private UserDAO userRepository;
@Autowired
private SystemRoleDAO systemRoleRepository;
@Override
@Transactional(rollbackFor = ResourceException.class)
public User create(User user) throws ResourceException {
try {
SystemRole role1 = systemRoleRepository.findOne(6l);
user.setUserRole(Lists.newArrayList(role1));
user.setId(62l); // !!! if set user ID - it works CORRECT
final User saved = userRepository.save(user);
return saved;
} catch (DataIntegrityViolationException ex) {
...
的UserDAO:
@Repository
public interface UserDAO extends JpaRepository<User, Long> {
...
SystemRoleDAO:
@Repository
public interface SystemRoleDAO extends JpaRepository<SystemRole, Long> {
它的工作原理,但我有3个刀片。
当我创建一个新用户时,我需要从列表中选择一个角色,将其添加到用户并保存新用户。
非常感谢。
请明确 – 2014-10-10 08:54:21
你如何分配的角色?看起来您正在创建新角色,而不是使用现有角色。并且请避免使用像List这样的rawtypes。改用'列表'代替。 –
Tom
2014-10-10 08:54:27
我猜想有一个插入,因为角色,因为你创建一个新的角色,而不是分配一个现有的,但你需要发布的代码创建和保存。 – 2014-10-10 08:54:38