我在写函数时遇到问题。我试图将输入流转换为字符串值。我写了两个函数,我试图提取字符串值,但我的Log.e响应返回NULL。以下是我的语法。我究竟做错了什么?由于在Java Android应用程序中将输入流转换为字符串值
public JSONArray GetCityDetails(String StateID) {
@SuppressWarnings("deprecation")
String url = "http://mywebsite.com/getCity.php?StateID="+URLEncoder.encode(StateID);
HttpEntity httpEntity = null;
try{
DefaultHttpClient httpClient = new DefaultHttpClient();
HttpGet httpGet = new HttpGet(url);
HttpResponse httpResponse = httpClient.execute(httpGet);
httpEntity = httpResponse.getEntity();
} catch(ClientProtocolException e){
e.printStackTrace();
} catch(IOException e){
e.printStackTrace();
}
JSONArray jsonArray = null;
if(httpEntity !=null){
try{
InputStream entityResponse = httpEntity.getContent();
// not working
String entityResponseAfterFunctionCall2 = readFully(entityResponse);
// not working
String entityResponseAfterFunctionCall3 = letsDoThisAgain(entityResponse);
Log.e("Entity Response Dude: ", entityResponseAfterFunctionCall3);
jsonArray = new JSONArray(entityResponseAfterFunctionCall3);
} catch(JSONException e){
e.printStackTrace();
} catch(IOException e){
e.printStackTrace();
}
}
return jsonArray;
}
public String readFully(InputStream entityResponse) throws IOException {
ByteArrayOutputStream baos = new ByteArrayOutputStream();
byte[] buffer = new byte[1024];
int length = 0;
while ((length = entityResponse.read(buffer)) != -1) {
baos.write(buffer, 0, length);
}
return baos.toString();
}
public String letsDoThisAgain(InputStream entityResponse){
InputStreamReader is = new InputStreamReader(entityResponse);
StringBuilder sb = new StringBuilder();
BufferedReader br = new BufferedReader(is);
try {
String read = br.readLine();
while(read !=null){
sb.append(read);
read = br.readLine();
}
} catch (IOException e) {
e.printStackTrace();
}
return sb.toString();
}
}
您只能读取输入流一次,除非它被缓冲,您可以重置它。 – njzk2 2014-09-22 21:33:11
@ njzk2 \t \t'而(bis.available()> 0){ \t \t \t而(读!= NULL){ \t \t \t \t sb.append(读); \t \t \t \t read = br.readLine(); \t \t \t} \t \t \t bis.reset(); '我把它放到我的** letsDoThisAgain **中,现在我得到这个错误**在字符0处输入结束** – bobhope 2014-09-24 14:11:29
'reset'与'mark'一起工作,但您需要检查'isMarkSupported “首先。 – njzk2 2014-09-24 14:24:15