MySQL的ORDER BY XY/X ASC

Question

我要订购此规则上升MySQL查询：x-y/x

X =价格

Y = price2

价格和price2是从MySQL中的列表。

我有这个查询，但不幸的是没有工作。

SELECT * 
FROM albums 
WHERE price2 > 1 
ORDER BY price - price2/price ASC 

感谢您的关注。

Answer 1

尝试了这一点：

$SQLquery = "SELECT * FROM albums WHERE price2 > 1 ORDER BY (price-price2)/price ASC"; 

或

$SQLquery = "SELECT * FROM albums WHERE price2 > 1 ORDER BY ((price-price2)/price) ASC"; 

Answer 2

你应该尝试：

SELECT * FROM albums 
WHERE price2 > 1 
ORDER BY ((price - price2)/price) ASC 

或

SELECT albums.*, ((price - price2)/price) myvar FROM albums 
WHERE price2 > 1 
ORDER BY myvar ASC 

Answer 3

顺序按基于指定列的作品。您可以从基表中创建一个视图或临时表，其中包含一个具有基于该公式的值的新列，然后对该列进行排序。