2014-10-22 217 views
2

所以,我有以下简单的例子:为什么std :: remove_if认为shared_ptr <T>是一个谓词?

#include <iostream> 
#include <memory> 
#include <vector> 
#include <algorithm> 

using namespace std; 

struct foo 
{}; 


int main(void) 
{ 
    vector<shared_ptr<foo>> v; 

    auto f1 = make_shared<foo>(); 
    auto f2 = make_shared<foo>(); 
    auto f3 = make_shared<foo>(); 
    auto f4 = make_shared<foo>(); 

    v.push_back(f1); 
    v.push_back(f2); 
    v.push_back(f3); 
    v.push_back(f4); 

    cout << v.size() << endl; 

    v.erase(remove_if(begin(v), end(v), f2), end(v)); 

    cout << v.size() << endl; 
} 

为什么这个remove_if认为f2是谓语,而不是我在找一个价值?我真的必须在这里提供一个谓词来使这个工作 - 或者我在这里做错了什么?

(注:编译器:GCC 4.8.2 -std = C++ 11)

编辑:应该有RTFM!无论如何 - 这里是编译器输出:

In file included from /usr/local/gcc/4.8.2/include/c++/4.8/algorithm:62:0, 
       from remove_if.cpp:4: 
/usr/local/gcc/4.8.2/include/c++/4.8/bits/stl_algo.h: In instantiation of '_FIter std::remove_if(_FIter, _FIter, _Predicate) [with _FIter = __gnu_cxx::__normal_iterator<std::shared_ptr<foo>*, std::vector<std::shared_ptr<foo> > >; _Predicate = std::shared_ptr<foo>]': 
remove_if.cpp:29:41: required from here 
/usr/local/gcc/4.8.2/include/c++/4.8/bits/stl_algo.h:1150:33: error: no match for call to '(std::shared_ptr<foo>) (std::shared_ptr<foo>&)' 
     if(!bool(__pred(*__first))) 
           ^
/usr/local/gcc/4.8.2/include/c++/4.8/bits/stl_algo.h: In instantiation of '_RandomAccessIterator std::__find_if(_RandomAccessIterator, _RandomAccessIterator, _Predicate, std::random_access_iterator_tag) [with _RandomAccessIterator = __gnu_cxx::__normal_iterator<std::shared_ptr<foo>*, std::vector<std::shared_ptr<foo> > >; _Predicate = std::shared_ptr<foo>]': 
/usr/local/gcc/4.8.2/include/c++/4.8/bits/stl_algo.h:4465:41: required from '_IIter std::find_if(_IIter, _IIter, _Predicate) [with _IIter = __gnu_cxx::__normal_iterator<std::shared_ptr<foo>*, std::vector<std::shared_ptr<foo> > >; _Predicate = std::shared_ptr<foo>]' 
/usr/local/gcc/4.8.2/include/c++/4.8/bits/stl_algo.h:1144:64: required from '_FIter std::remove_if(_FIter, _FIter, _Predicate) [with _FIter = __gnu_cxx::__normal_iterator<std::shared_ptr<foo>*, std::vector<std::shared_ptr<foo> > >; _Predicate = std::shared_ptr<foo>]' 
remove_if.cpp:29:41: required from here 
/usr/local/gcc/4.8.2/include/c++/4.8/bits/stl_algo.h:214:23: error: no match for call to '(std::shared_ptr<foo>) (std::shared_ptr<foo>&)' 
    if (__pred(*__first)) 
        ^
/usr/local/gcc/4.8.2/include/c++/4.8/bits/stl_algo.h:218:23: error: no match for call to '(std::shared_ptr<foo>) (std::shared_ptr<foo>&)' 
    if (__pred(*__first)) 
        ^
/usr/local/gcc/4.8.2/include/c++/4.8/bits/stl_algo.h:222:23: error: no match for call to '(std::shared_ptr<foo>) (std::shared_ptr<foo>&)' 
    if (__pred(*__first)) 
        ^
/usr/local/gcc/4.8.2/include/c++/4.8/bits/stl_algo.h:226:23: error: no match for call to '(std::shared_ptr<foo>) (std::shared_ptr<foo>&)' 
    if (__pred(*__first)) 
        ^
/usr/local/gcc/4.8.2/include/c++/4.8/bits/stl_algo.h:234:23: error: no match for call to '(std::shared_ptr<foo>) (std::shared_ptr<foo>&)' 
    if (__pred(*__first)) 
        ^
/usr/local/gcc/4.8.2/include/c++/4.8/bits/stl_algo.h:238:23: error: no match for call to '(std::shared_ptr<foo>) (std::shared_ptr<foo>&)' 
    if (__pred(*__first)) 
        ^
/usr/local/gcc/4.8.2/include/c++/4.8/bits/stl_algo.h:242:23: error: no match for call to '(std::shared_ptr<foo>) (std::shared_ptr<foo>&)' 
    if (__pred(*__first)) 
+1

这种混淆会更清晰一些编译器输出和您期望的输出。 – 2014-10-22 10:41:33

+1

此代码不能编译。我不明白 – P0W 2014-10-22 10:42:54

+0

我会删除,但是Mike已经正确回答了,所以我不会删除,但是如果它确实关闭了 - 那就这样吧.. – Nim 2014-10-22 10:45:18

回答

7

因为这就是remove_if所做的;第三个参数是测试是否删除元素的谓词。据推测,你的代码无法编译,因为shared_ptr不能被称为函数。

如果要删除具有特定值的元素,请使用remove

+1

“std :: shared_ptr ”是一个谓词吗?如果没有'operator()',我会认为这会失败。 – 2014-10-22 10:38:19

+1

arrgggh !!!刚注意到血腥的文档(它在cppreference的相同页面上)doh! – Nim 2014-10-22 10:38:50

+5

@LightnessRacesinOrbit:不是。但'remove_if'会试图把它看作一个,可能无法编译。 – 2014-10-22 10:38:57

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