我一直在梳理wiki的jqgrid,我似乎无法弄清楚如何改变我的控制器中的逻辑jqgrid搜索。Jqgrid控制器调整搜索
我假设搜索将使用在jqgrid中指定的相同URL。这是我的jqgrid调用的动作逻辑。我使用的是Spring 3.0及其Java控制器。
@RequestMapping(value = "studentjsondata", method = RequestMethod.GET)
public @ResponseBody String studentjsondata(HttpServletRequest httpServletRequest) {
Format formatter = new SimpleDateFormat("MMMM dd, yyyy");
String column = "id";
if(httpServletRequest.getParameter("sidx") != null){
column = httpServletRequest.getParameter("sidx");
}
String orderType = "DESC";
if(httpServletRequest.getParameter("sord") != null){
orderType = httpServletRequest.getParameter("sord").toUpperCase();
}
int page = 1;
if(Integer.parseInt(httpServletRequest.getParameter("page")) >= 1){
page = Integer.parseInt(httpServletRequest.getParameter("page"));
}
int limitAmount = 10;
int limitStart = limitAmount*page - limitAmount;
List<Person> students = Person.findStudentPeopleOrderByColumn(true, column, orderType, limitStart, limitAmount).getResultList();
long countStudents = Student.countStudents();
double tally = Math.ceil(countStudents/10.0d);
int totalPages = (int)tally;
long records = countStudents;
StringBuilder sb = new StringBuilder();
sb.append("{\"page\":\"").append(page).append("\", \"records\":\"").append(records).append("\", \"total\":\"").append(totalPages).append("\", \"rows\":[");
boolean first = true;
for (Person s: students) {
sb.append(first ? "" : ",");
if (first) {
first = false;
}
sb.append(String.format("{\"id\":\"%s\", \"cell\":[\"%s\", \"%s\", \"%s\", \"%s\", \"%s\", \"%s\"]}",s.getId(), s.getId(), s.getFirstName(), s.getLastName(), formatter.format(s.getDateOfBirth().getTime()), s.getGender(), s.getMaritalStatus()));
}
sb.append("]}");
return sb.toString();
}
,这里是我的navGrid decleration
$("#studentGrid").jqGrid('navGrid', "#pager", {edit:false,add:false,del:false,search:true},{ },{ },{ },
{
sopt:['eq', 'ne', 'lt', 'gt', 'cn', 'bw', 'ew'],
closeOnEscape: true,
multipleSearch: true,
closeAfterSearch: true
}
);
这是我colModel和colNames
colNames:['id','First Name', 'Last Name', 'Date Of Birth', 'Gender', 'Marital Status'],
colModel:[
{name:'id',index:'id', width:15},
{name:'firstName',index:'firstName', width:30, formoptions:{elmprefix:'(*) '}, editable:true, edittype: 'text', editrules:{required:true}},
{name:'lastName',index:'lastName', width:30, formoptions:{elmprefix:'(*) '}, editable:true, edittype: 'text',editrules:{required:true}},
{name:'dateOfBirth',index:'dateOfBirth', width:30, formoptions:{elmprefix:'(*) '},editrules:{required:true}, editable:true, edittype: 'text',
editoptions: {
dataInit: function(element) {
$(element).datepicker({dateFormat: 'MM dd, yy'})
}
}
},
{name:'gender',index:'gender', width:30, formoptions:{elmprefix:'(*) '}, editable:true, editrules:{required:true}, edittype: 'select',
editoptions:{value:{}}
},
{name:'maritalStatus',index:'maritalStatus', width:30, formoptions:{elmprefix:'(*) '}, editable:true, editrules:{required:true}, edittype: 'select',
editoptions:{value:{}}
}
]
因为它是,默认情况下搜索使用trhe searchGrid方法。在帖子数组中存在_search: true
和filters: {"groupOp":"AND","rules":[{"field":"firstName","op":"eq","data":"Anil"}]}
。 searchField,searchOper和searchString都是空的,但存在于epost数组中。
我该怎么做才能使搜索工作?
我是否必须使用json解析器和filters数组将json解析为Java,然后通过添加where子句并使用Json对象的值来更改我的查询?
jqgrid查询自己的数据对象是否回到服务器并启动新的查询?
我不太确定我要做什么,请提供某种形式的指导。
我在代码中看不到类似'httpServletRequest.getParameter(“filters”)''和'httpServletRequest.getParameter(“_ search”)''的东西。 – Oleg 2012-03-26 14:41:44
我还没有做出改变,因为我不确定如何处理这些值。我是否将它作为arg传递给我的查找器,并将其解析为json形式的java到那里?我不确定该操作通常使用哪种模式来启用搜索功能。这些值可以像上面概述的那样访问。 – Binaryrespawn 2012-03-26 14:46:48
我已经看到这个页面http://blog.brzezinka.eu/webmaster-tips/jquery/how-to-enable-the-search-functionality-in-jqgrid它是在PHP中完成的,我在java中做到了这一点?这是通常的做法吗? – Binaryrespawn 2012-03-26 14:55:58