2011-12-02 28 views

回答

1

你可以简单地使用jQuery的AJAX函数发送到服务器的请求,并听取了错误(即:超时)

var request = $.ajax({ 
    url: "http://somewebsite.com", 
    type: "POST" 
}); 

request.done(function(msg) { 
    $("#log").html("Website is up."); 
}); 

request.fail(function(jqXHR, status) { 
    $("#log").html("Website is down."); 
});